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3 years ago

if the accepted thickness of aluminum foil is 1.5x10^5 is your answer percise, accurate or both. explain your answer

Physics

1 answer:

viva [34]3 years ago

5 0

Answer:

The answer is 150,000

Explanation:

I got my answer by solving 10^5 which is 100,000 then you just multiply 1.5 to get 150,000

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A point charge with a charge q1 = 4.00 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC mo

GrogVix [38]

Answer:

W = -0.480 J

Explanation:

given,

q₁ = 4 μC

q₂ = -4.10 μC

$W = kq_1q_2(\dfrac{1}{a}+\dfrac{1}{b})$

$b = \sqrt{(0.27-0)^2+(0.27-0)^2}$

b = 0.381

k = 8.99 × 10⁹ Nm²/C²

$W = 8.99\times 10^9\times 4\times 10^{-6}\times (-4.1 \times 10^{-6})(\dfrac{1}{0.17}+\dfrac{1}{0.381})$

$W = [-147.436\times (5.88-2.62)\times 10^{-3}]J$

W = -0.480 J

Work done by the electric force W = -0.480 J

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3 years ago

A golf ball traveling 3m/s to the right collides in a head-on collision with a stationary bowling ball in a friction-free enviro

Vladimir79 [104]

Answer: equal to 3 m/s

Explanation:

Speed of golf ball will be equal to 3 m/s because in Perfect Elastic Collision Energy is conserved .

So speed of golf ball will be same in order to Satisfy

Initial Kinetic Energy =Final Kinetic Energy

Considering Bowling ball remains at rest after collision other wise some energy will also be acquired by bowling ball which automatically decreases the amount of Kinetic Energy of golf ball resulting its speed to decrease by some extent.

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3 years ago

The two conducting rails in the drawing are tilted upwards so they each make an angle of 30.0° with respect to the ground. The v

dolphi86 [110]

Answer:

The current flows through the rod is 14.9 A.

Explanation:

Given that,

Magnetic field = 0.045 T

Mass of aluminum rod = 0.19 kg

Length = 1.6 m

Angle = 30.0°

We need to calculate the force

Using resolving force

$F\cos\theta=mg\sin\theta$

$F=mg\tan\theta$

Put the value into the formula

$F=0.19\times9.8\times\tan30$

$F=1.075\ N$

We need to calculate the current flows through the rod

Using formula of magnetic force

$F=iLB$

$i=\dfrac{F}{LB}$

Put the value into the formula

$i=\dfrac{1.075}{1.6\times0.045}$

$i=14.9\ A$

Hence, The current flows through the rod is 14.9 A.

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3 years ago

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makkiz [27]

Because,

In left image pin is not touch to the wire.

In right image pin is touch to the wire.

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