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3 years ago

if the accepted thickness of aluminum foil is 1.5x10^5 is your answer percise, accurate or both. explain your answer

Physics

1 answer:

viva [34]3 years ago

5 0

Answer:

The answer is 150,000

Explanation:

I got my answer by solving 10^5 which is 100,000 then you just multiply 1.5 to get 150,000

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An empty truck and a fully loaded truck are next to each other at the traffic light. When the light turns green the lighter truc

Lilit [14]

This is correct. The lighter truck moves faster.

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3 years ago

According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 L container at 267.6 K should exert a pressure of 13

luda_lava [24]

Answer:

% differ 1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

$(P+ \frac{n^2 *a}{v^2}) (V - nb) = nRT$

$(P+ (\frac{1.074^2 *1.360}{1.746^2})) (1.746 - 1.074*3.183*10^{-2}) = 1.074*0.0821*267.6$

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ $= \frac{ P_I - P_v}{P_I} *100$

$= \frac{13.51 - 13.27}{13.51} *100$

= 1.72%

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3 years ago

Can you walk on the moon

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2 years ago

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Which statement about the effects of medium on the speed of a mechanical wave is true?

Anastasy [175]

C. A mechanical wave generally travels faster in gases than liquids.

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3 years ago

The electric field strength in the space between two closely spaced parallel disks is 1.0 10^5 N/C. This field is the result of

alex41 [277]

To solve this problem it is necessary to apply the concepts related to the capacitance in the disks, the difference of the potential and the load in the disc.

The capacitance can be expressed in terms of the Area, the permeability constant and the diameter:

$C = \frac{\epsilon_0 A}{d}$

Where,

$\epsilon_0$ = Permeability constant

A = Cross-sectional Area

d = Diameter

Potential difference between the two disks,

V = Ed

Where,

E = Electric field

d = diameter

Q = Charge on the disk equal to $\rightarrow Q=ne=(3.9*10^9)(1.6*10^{-19})= 6.24*10^{-10}C$

Through the value found and the expression given for capacitance and potential, we can define the electric charge as

$Q = CV$

$Q = \frac{\epsilon A}{d}(Ed)$

$Q = \epsilon_0 AE$

$Q = \epsilon_0 \pi(\frac{d}{2})^2E$

$Q = \frac{\epsilon \pi d^2E}{4}$

Re-arranging the equation to find the diameter of the disks, the equation will be:

$d = \sqrt{\frac{4D}{\epsilon_0 \pi E}}$

Replacing,

$d = \sqrt{\frac{4(6.24*10^{-10})}{(8.85*10^{-12})\pi(1*10^{5})}}$

$d = 0.0299m$

Therefore the diameter of the disks is 0.03m

8 0

2 years ago