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4 years ago

What is neutralization?

Chemistry

2 answers:

Natalka [10]4 years ago

8 0

When an acid and an alkali neutralise each other to produce a neutral substance (pH7)

agasfer [191]4 years ago

5 0

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. The neutralization of a strong acid and strong base has a pH equal to 7. The neutralization of a strong acid and weak base will have a pH of less than 7, and conversely, the resulting pH when a strong base neutralizes a weak acid will be greater than 7.

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I have a science fair soon and I need to make a interesting experiment but I want it to be easy in the same time. Can you please

agasfer [191]

You should make a density trap, you get different liquids with different density's ( corn starch , water , alcohol , syrup) and pour them into a big vase and the different density's will sit on top of each other . the best thing to do is to use food coloring so that each level is a different color.

4 0

3 years ago

Read 2 more answers

How does heat differ from temperature?

mote1985 [20]

Answer: Option (c) is the correct answer.

Explanation:

Temperature is used as for measuring the average kinetic energy present in a substance or object.

The internal kinetic energy obtained by the molecules of an object is known as thermal energy.

Hence, temperature measures the thermal energy of an object.

Whereas when this thermal energy flows from a hotter object to a cooler object which are placed adjacent to each other then it is known that heat is flowing.

Thus, we can conclude that heat differ from temperature as temperature measures thermal energy, and heat is the flow of thermal energy.

7 0

3 years ago

Read 2 more answers

Calculate the pH after the addition of 10.0 mL of 0.240 M sodium hydroxide to 50.0 mL of 0.120 M acetic acid.

Goryan [66]

Answer:

pH = 4.58

Explanation:

The reaction of NaOH with acetic acid, CH₃COOH occurs as follows:

NaOH + CH₃COOH → CH₃COO⁻Na⁺ + H₂O

<em>Moles that react:</em>

NaOH = 10mL = 0.010L * (0,240mol / L) = 0.0024 moles NaOH

CH₃COOH = 50.0mL = 0.050L * (0.120mol / L) = 0.0060 moles CH₃COOH

That means after the reaction you will have:

CH₃COOH: 0.0060 mol - 0.0024 mol = 0.0036 moles

CH₃COO⁻Na⁺: 0.0024 moles

in solution, you will have the mixture of a weak acid (Acetic acid), with its conjugate base (sodium acetate, CH₃COO⁻Na⁺). And pH of this buffer can be determined using H-H equation:

pH = pKa + log [A⁻] / [HA]

For Acetic buffer pKa = 4.76:

pH = 4.76 + log [CH₃COO⁻Na⁺] / [CH₃COOH]

<em>Where [] is molarity of each species or moles</em>

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Replacing:

pH = 4.76 + log [0.0024 moles] / [0.0036 moles]

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6 0

3 years ago

The atomic radius of a gold atom is 144×10^-12. The volume of a gold atom can be calculated using the volume of a sphere. The de

Alekssandra [29.7K]

Given:
Atomic radius of gold = 144 x 10⁻¹² m = 144 pm
Density of gold = 19.3 g/cm³ = 19.3 x 10⁻³ kg/cm³
Mass of gold sample = 1.40 g = 1.4 x 10⁻³ kg

Calculate the volume of an atom.
v = [(4π)/3]*(144 x 10⁻¹² m)³ = 1.2508 x 10⁻²⁹ m³

Calculate the mass of an atom.
$m=(1.2508\tmes10^{-29}\,m^{3})*(19.3\times 10^{-3}\, \frac{kg}{cm^{3}} )*(10^{2}\, \frac{cm}{m})^{3} \\ = 2.4142 \times 10^{-25} \, kg$

Calculate the number of atoms in a sample of mass 1.40 g.
$N = \frac{1.40 \time 10^{-3} kg}{2.4142 \times 10^{-25} \, \frac{kg}{atom} } =5.8 \times 10^{21} \, atoms$

Answer: 5.8 x 10²¹ atoms

3 0

3 years ago

What is the role of a strong acid catalyst in an elimination reaction?

Ivan

Explanation:

An elimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one or two-step mechanism. The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction.

Another definiton is;

Elimination reaction, any of a class of organic chemical reactions in which a pair of atoms or groups of atoms are removed from a molecule, usually through the action of acids, bases, or metals and, in some cases, by heating to a high temperature. It is the principal process by which organic compounds containing only single carbon-carbon bonds (saturated compounds) are transformed to compounds containing double or triple carbon-carbon bonds (unsaturated compounds).

Strong Acids play two key roles in elimination reactions:

1. Without the acid catalyst, the reaction is painfully slow.

2. Acid greatly facilitates elimination of the leaving group.

8 0

4 years ago