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Katena32 [7]
2 years ago
11

Help pleaseeee my brainnn stopped working once again lol

Physics
2 answers:
Andrew [12]2 years ago
6 0

Answer:

1c 2a 3b  

Explanation:

julia-pushkina [17]2 years ago
3 0
1c 2a 3b for the answers ———
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What is the gravitational force on a 35.0 kg object standing on the Earth's surface?
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F=mg
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Jimmy is standing 300 feet away from a rocket that is being shot up into the air away from him at an angle of elevation of 70 de
ira [324]

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Explanation: see attachment.

Opp/ Adj = Tan 70°

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A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

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Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

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Which countries were considered the three major Axis Powers?
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