Please help!?!?

Physics

2 answers:

Vanyuwa [196]4 years ago

5 0

Since bulb is connected in the closed circuit at the position of D

as well as switch B is also closed in that position so the current will flow through the bulb and bulb will glow in that position

So the most appropriate correct option will be

D. The light bulb will be on

fiasKO [112]4 years ago

4 0

Answer:

D. The light bulb will be on

Explanation:

When a bulb is placed at D it works like a load and will draw the current. The circuit will remain open until the switch B is closed. Once B is closed, the current will start flowing through the bulb and it will turn on.

It can be understood through an experiment as will. You can connect a small LED with a battery and see for yourself that the LED turns on.

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3 years ago

A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the s

Ira Lisetskai [31]

The elastic potential energy (Ep) is given by $Ep = \frac{1}{2}*k*x^2$

Data:
Ep = 5184 J
k = 16200 N/m
x (displacement) = ?

Solving:
$Ep = \frac{1}{2}*k*x^2$
$5184 = \frac{1}{2}*16200*x^2$
$5184*2 = 16200x^2$
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$\boxed{\boxed{x = 0.8\:m}}\end{array}}\qquad\quad\checkmark$

8 0

4 years ago

Read 2 more answers

Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.

velikii [3]

Answer:

$V = \frac{V_0x}{d}$

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

$E= -\frac{\Delta V}{x}$ (1)