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Zolol [24]
3 years ago
15

Please help!?!?

Physics
2 answers:
Vanyuwa [196]3 years ago
5 0

Since bulb is connected in the closed circuit at the position of D

as well as switch B is also closed in that position so the current will flow through the bulb and bulb will glow in that position

So the most appropriate correct option will be

D. The light bulb will be on

fiasKO [112]3 years ago
4 0

Answer:

D. The light bulb will be on

Explanation:

When a bulb is placed at D it works like a load and will draw the current. The circuit will remain open until the switch B is closed. Once B is closed, the current will start flowing through the bulb and it will turn on.

It can be understood through an experiment as will. You can connect a small LED with a battery and see for yourself that the LED turns on.

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Read 2 more answers
The work function (energy needed to remove an electron) of gold is 5.1 eV. Two pieces of gold (at the same potential) are separa
scoundrel [369]

Answer:

The value of L is 0.3 nm.

Explanation:

Given that,

Energy \phi= 5.1 eV

Transmission probability = 10⁻³

We need to calculate the value of L

We know that,

Formula of tunneling probability

T=Ge^{-2kL}....(I)

Where,

k=\dfrac{\sqrt{2m(E-U)}}{\hbar}....(II)

Where, m = mass of electron

E = \phi+U

\phi = E-U

Put the value in equation (II)

k=\dfrac{\sqrt{2\times9.1\times10^{-31}\times5.1\times1.6\times10^{-19}}}{1.055\times10^{-34}}

k=1.155\times10^{10} m^{-1}

From equation (I)

ln T=-2kLG

L=\dfrac{ln T}{-2kG}

L=\dfrac{ln 10^{-3}}{-2\times1.155\times10^{10}\times1}

L=2.99\times10^{-10}\ m

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L=0.3\ nm

Hence, The value of L is 0.3 nm.

7 0
3 years ago
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