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2 years ago

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1 answer:

3 0

The increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.

<h3>How to calculate temperature change?</h3>

The temperature change of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed or released
m = mass of substance
c = specific heat capacity
∆T = change in temperature

5000 = 225 × 0.385 × ∆T

5000 = 86.63∆T

∆T = 5000/86.63

∆T = 57.72°C

Therefore, the increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.

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2 years ago

Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an

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Answer:

a) 2.43 m/s

b) 4.83 m/s

c) 0.023 m/s²

Explanation:

a) Both cars cover a distance of 510 m in 210 s. Since car A has no acceleration

Speed = Distance / Time

$\text{Speed}=\frac{510}{210}=2.43\ m/s$

Velocity of car A is 2.43 m/s

t = Time taken = 210 seconds

u = Initial velocity

v = Final velocity

s = Displacement = 510 m

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$s=ut+\frac{1}{2}at^2\\\Rightarrow 510=0\times 210+\frac{1}{2}\times a\times 210^2\\\Rightarrow a=\frac{510\times 2}{210^2}\\\Rightarrow a=0.023\ m/s^2$

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3 years ago

A 795-loop square armature coil with a side of 10. 5 cm rotates at 70. 0 rev/s in a uniform magnetic field of strength 0. 45 t.

Agata [3.3K]

The rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

RMS is an acronym for root mean squared. An RMS value is more than just the "amount of AC power that causes the same heating impact as an analogous DC power" or something along those lines.

No. of loop = 795

Diameter of the coil = 10.5 cm

Radius of the coil = 5.25 cm

Magnetic Field, B = 0.45 T

Time, t = 70.0 rev/s

$V_{rms} =\frac{NwAB}{\sqrt{2} }$

Where,

N = No. of loop

A = Area of the coil

B = Magnetic Field

$V_{rms}$ = Voltage rms

Area of the coil = πr²

= 86.57 cm²

w = 2π/t

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= 0.089

$V_{rms} =\frac{795*0.089*86.57* 0.45}{\sqrt{2} }\\\\V_{rms} =\frac{2756.36}{\sqrt{2} }\\\\\\V_{rms} =\frac{2756.36}{1.414 }\\\\V_{rms} = 1.94 * 10^-^5 V$

Therefore, the rms voltage output of the generator is 1.94 × 10⁻ ⁵ V.

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