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Leona [35]
2 years ago
8

Match each item with the clean water regulation it describes. (2 points)

Physics
1 answer:
Leona [35]2 years ago
6 0

The correct match of each item to the clean water regulation it describes is as follows:

  • Regulates pollutants discharged into surface waters: Clean water act
  • Covers both surface and ground waters: Safe drinking water act
  • Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
  • Funds sewage treatment plants: Clean water act

<h3>What are the functions of clean water regulation?</h3>

Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.

On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.

Therefore, the correct match of each item to the clean water regulation it describes is as follows:

  • Regulates pollutants discharged into surface waters: Clean water act
  • Covers both surface and ground waters: Safe drinking water act
  • Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
  • Funds sewage treatment plants: Clean water act

Learn more about clean water regulation at: brainly.com/question/2142268

#SPJ1

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Tungsten has a temperature coefficient of resistivity of 0.0045 (c°)-1. a tungsten wire is connected to a source of constant vol
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Answer:

131.1^{\circ}C

Explanation:

The power delivered in the wire is given by:

P=\frac{V^2}{R}

where V is the voltage of the battery and R is the resistance of the wire.

Since the voltage of the battery is constant, we can rewrite this equation as follows:

V^2 = PR=const. (1)

At the beginning, the initial resistance is R_0, and the power delivered is P_0. Later, when the temperature increases, the power becomes P_1 = \frac{2}{3}P_0, and the new resistance is R_1. Using (1), we can write

P_0 R_0 = \frac{2}{3}P_0 R_1\\R_1 = \frac{3}{2}\frac{P_0 R_0}{P_0}=\frac{3}{2}R_0 (2)

So, the new resistance must be 3/2 of the initial resistance.

We know that the resistance increases linearly with the temperature, as

R_1 = R_0 (1+\alpha \Delta T)

where

\alpha = 0.0045 ^{\circ}C^{-1} is the temperature coefficient

\Delta T is the change in temperature

Using (2), we can rewrite this equation as

\frac{3}{2}R_0 = R_0(1+ \alpha \Delta T)

and we find:

\frac{3}{2}=1+\alpha \Delta T\\\Delta T=\frac{\frac{3}{2}-1}{\alpha}=111.1 ^{\circ}

So, the new temperature of the wire must be

T_f = 21^{\circ}+111.1^{\circ}=132.1^{\circ}

6 0
3 years ago
How much work did the movers do (horizontally) pushing a 46.0-kg crate 10.4 m across a rough floor without acceleration, if the
creativ13 [48]

Answer:

The total work done by the mover is 2.81 kJ.

Explanation:

Given the 46 kg crate is displaced by 10.4 meters.

And the acceleration is zero. Also, \mu_k=0.60

let P is applied force, F_N is the net force, m is the mass and g=9.81\ m/s^2

and \mu_k=0.60

F_N=P- \mu_k\times mg

As the acceleration is zero, the net force will also be zero.

0=P- \mu_k\times mg\\P=\mu_k\times mg.

P=0.6\times 46\times 9.81=270.76\ N

Now, we know the work done is force times displacement.

So,

W=P\times d\\W=270.76\times 10.4=2815.90\ J\\W=2.81\ kJ

So, the total work done by the mover to displace 46 kg crate by 10.4 meters 2.81 kJ.

5 0
3 years ago
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