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kirill115 [55]
2 years ago
7

A body of mass m, = 0.050 kg and initial velocity v₁ = 9 m / s turned to the right collides with a body of mass m₂ = 0.030 g wit

h unknown initial velocity v₂. After the collision, the two bodies join together and have a final velocity vy = 6 m / s to the right. Using the momentum conservation theorem, find the initial velocity v₂
Physics
1 answer:
Ugo [173]2 years ago
6 0

Answer:

Suppose two objects of different masses are moving with different velocities in the same direction on a straght-line before collision. After collision, they stick together and move with common (the same) velocity

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Explanation:

(a)

Since the earth is assumed to be a sphere.

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(c)

Write the ideal gas equation as follows:

PV =nRT
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no.\, of\, molecules = 0.0196 moles \times\frac{6.022\times10^{23} molecules}
{Imole}= 1.2\times 10^{23} molecules

Hence the required molecules in Caesar breath is 1.2\times 10^{23} molecules

(d)

Volume fraction in Caesar last breath is as follows:  

Fraction,\, X =\frac{12\times 10 molecules}{13.3\times 10^{43} \,molecules}= 9.0\times 10\, molecule/air\, molecule}

(e)

Since the volume capacity of the human body is 500 mL.

Volume\, of\, Caesar\, nreath\, inhale\, is =\frac{ 12\times 10^{22}\, molecules}{breath}\times \frac{9.0\times10^{-23} molecule}{air\, molecule}\\\\= 1.08 molecule/breath

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