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Elena L [17]
4 years ago
13

A rigid tank having a volume of 0.100 m3 contains helium gas at 150 atm. how many balloons can be inflated by opening the valve

at the top of the tank? each filled balloon is a sphere 0.300 m in diameter at an absolute pressure of 1.20 atm
Physics
1 answer:
GalinKa [24]4 years ago
4 0
The initial value of P*V = 0.100*150 atm-m³ 
<span> Each balloon has a volume of (4/3)*π*r³ and N balloons have a volume of N*(4/3)*π*r³ 
</span><span> When all the balloons are inflated, the pressure in the tank is the same as the pressure in the balloons, so the final value of P*V is 
</span><span> 1.20*[N*(4/3)*π*r³ + 0.100] 
</span><span> 0.100*150 = 1.20*[N*(4/3)*π*r³ + 0.100] solve for N: 
</span><span> 15/1.2 = N*(4/3)*π*r³ + 0.100
</span><span> 12.5 - 0.100 = N*(4/3)*π*0.150³ 
</span><span> 12.4 = N*0.01414 
</span><span> N = 877</span>
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From equation of motion,

S = ut +  \frac{1}{2} a {t}^{2}  \\  \\ S = 4 \times 60 +   \frac{1}{2}  \times 3 \times  {60}^{2}  \\  \\ S = 240 + 5400 \\  \\ S = 5640 \: m

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4 0
3 years ago
Read 2 more answers
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8 0
3 years ago
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3 years ago
A 150 kg boy and his bike are traveling 12 m/s when he slams on his breaks and stop at his friend’s house. How much impulse is r
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So, the impulse is equal to 1800 kg-m/s

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3 years ago
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