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Elena L [17]
4 years ago
13

A rigid tank having a volume of 0.100 m3 contains helium gas at 150 atm. how many balloons can be inflated by opening the valve

at the top of the tank? each filled balloon is a sphere 0.300 m in diameter at an absolute pressure of 1.20 atm
Physics
1 answer:
GalinKa [24]4 years ago
4 0
The initial value of P*V = 0.100*150 atm-m³ 
<span> Each balloon has a volume of (4/3)*π*r³ and N balloons have a volume of N*(4/3)*π*r³ 
</span><span> When all the balloons are inflated, the pressure in the tank is the same as the pressure in the balloons, so the final value of P*V is 
</span><span> 1.20*[N*(4/3)*π*r³ + 0.100] 
</span><span> 0.100*150 = 1.20*[N*(4/3)*π*r³ + 0.100] solve for N: 
</span><span> 15/1.2 = N*(4/3)*π*r³ + 0.100
</span><span> 12.5 - 0.100 = N*(4/3)*π*0.150³ 
</span><span> 12.4 = N*0.01414 
</span><span> N = 877</span>
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Answer:

The mother has to sit 2.17 ft from the center on the other side of the seesaw.

Explanation:

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If the torque of the daughter on one side of the pivoting point is given by:

5.5 ft x 63.5 lb x g = 349.25 g ft lb

we need that the absolute value of the torque exerted by the mom (160.9 lb) to be the same in magnitude (and of course opposite direction). So we assume that "d" is the distance at which the mother locates to make this torque equal in magnitude to her daughter's torque:

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3 years ago
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andrezito [222]

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3 years ago
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