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Elena L [17]
3 years ago
13

A rigid tank having a volume of 0.100 m3 contains helium gas at 150 atm. how many balloons can be inflated by opening the valve

at the top of the tank? each filled balloon is a sphere 0.300 m in diameter at an absolute pressure of 1.20 atm
Physics
1 answer:
GalinKa [24]3 years ago
4 0
The initial value of P*V = 0.100*150 atm-m³ 
<span> Each balloon has a volume of (4/3)*π*r³ and N balloons have a volume of N*(4/3)*π*r³ 
</span><span> When all the balloons are inflated, the pressure in the tank is the same as the pressure in the balloons, so the final value of P*V is 
</span><span> 1.20*[N*(4/3)*π*r³ + 0.100] 
</span><span> 0.100*150 = 1.20*[N*(4/3)*π*r³ + 0.100] solve for N: 
</span><span> 15/1.2 = N*(4/3)*π*r³ + 0.100
</span><span> 12.5 - 0.100 = N*(4/3)*π*0.150³ 
</span><span> 12.4 = N*0.01414 
</span><span> N = 877</span>
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A potato is launched from the ground at an 73 degree angle with a velocity of 48 m/s.
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Answer:

107.4 meters

Explanation:

gravity is 9.8m/s^2

max height = (velocity squared times sin squared angle) ÷ ( speed of gravity times 2 )

max height = (48 squared times sin of 73 squared) ÷ ( 9.8 times 2 )

8 0
2 years ago
A dc motor with its rotor and field coils connected in series has an internal resistance of 3.2 Ω. When running at full load on
pochemuha

Answer:

The current drawn by the motor from the line is 4.68 A.

Explanation:

Given that,

Internal resistance of the dc motor, r = 3.2 ohms

Voltage, V = 120 V

Emf in the motor, \epsilon=105\ V

We need to find the current drawn by the motor from the line. A dc motor with its rotor and field coils connected in series, applying loop rule we get :

V=\epsilon+Ir

I is current drawn by the motor

I=\dfrac{V-\epsilon}{r}\\\\I=\dfrac{120-105}{3.2}\\\\I=4.68\ A

So, the current drawn by the motor from the line is 4.68 A. Hence, this is the required solution.

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3 years ago
Identify one harmful environmental change that occurs when a volcano erupts.
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Many ecosystems and plants are damaged or destroyed when a volcano erupts.
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A hot iron ball of mass 200 g is cooled to a temperature of 22°C from 100°C. How much heat was
Nookie1986 [14]

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Q= -6900 J

Explanation:

use the formula Q=mC(T_2 - T_1) and sub in givens

Q=mC(T_2 - T_1)

Q= (200 g)(0.444 J/g°C)(22-100)

Q= -6900 J

The negative sign means heat is lost, which agrees with the decrease in temperature

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3 years ago
A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential differen
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The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

  • Work function is a material property defined as the minimum amount of energy  required to infinitely remove electrons from the surface of a particular solid.
  • The potential difference required to support all emitted electrons is called the stopping potential which is given by v_0=\frac{K.E_m_a_x}{e} .....(1)
  • where v_0 is the stopping potential and e is the charge of the electron given by 1.6\times10^-^1^9 .

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation  is given by:

K.E_m_a_x=E-\phi      ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

  ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV

As we know that E=\frac{hc}{\lambda}  ....(3)

where Speed of light,c = 3\times10^8 m/s and Planck's constant , h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs

From equation (3) , we get

\lambda=\frac{hc}{E} \\\\\lambda=\frac{  4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm

Learn about more einstein photoelectric equation  here:

brainly.com/question/11683155

#SPJ4

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1 year ago
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