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Answer:
The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>
Explanation:
Symbol of Si isotope
<u>Number of Neutron = Mass number - Atomic Number</u>
Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu
Atomic Number = Total number of Protons present in the nucleus.
Si = 14
Number of neutron = 24 - 14
= 14
An isotope of ₂₀⁴⁰X ⇒₂₀⁴⁴X
<h3>Further explanation </h3>The elements in nature have several types of isotopes
Isotopes are atoms that have the same number of protons and a different number of neutrons.
So Isotopes are elements that have the same Atomic Number (Proton)
In the following element notation,
X = symbol of elemental atom
A = mass number
= number of protons + number of neutrons
Z = atomic number
= number of protons = number of electrons, on neutral elements
For symbol of isotope X :
₂₀X⁴⁰ : atomic number = 20, mass number = 40
A. ₄₀²⁰X : atomic number = 40, mass number = 20, neutrons=20
B. ₂₀⁴⁰X²⁺ : atomic number = 20, mass number = 40, neutrons=20
C. ₂₁⁴⁰X : atomic number = 21, mass number = 40, neutrons=19
D. ₂₀⁴⁴X : atomic number = 20, mass number = 44, neutrons=22