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professor190 [17]
2 years ago
12

If a power source provides 54 watts of power to operate a machine that draws 4.5 amps of current when in use, what is the voltag

e used by the machine?
Physics
1 answer:
gregori [183]2 years ago
4 0

Answer:

.V=12v

Explanation:

P=VI

54W=V×4.5A

V=54W/4.5A

V=12V

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What should you do if your brakes fail? Hook your shoe under the pedal and see if you can free it. Pull the steering wheel back.
Zolol [24]

Answer: Try pumping the brake pedal to increase pressure.

Explanation:

When the brake of a vehicle fails when driving, it's important to pump the brake pedal to increase pressure.

Sometimes, there may be a soft brake due to the fact that the brake master cylinder of the vehicle cannot full pressure which is necessary for the braking power.

One should quickly pump the brake pedal with his or her foot so as to generate enough pressure which will be necessary in stopping safely.

4 0
3 years ago
How many grams are in 5 kilos​
s2008m [1.1K]

1 kilo = 1000 gms

Therefore, 5 kilo = 5000 gms

5 0
3 years ago
Read 2 more answers
A ball is launched upward at an angle from the ground. Which way does its velocity point at the top?
gogolik [260]
The answer is B because at the very top the acceleration is ZERO so it isn’t moving
7 0
3 years ago
An object is dropped from a height H. During the final second of its fall, it traverses a distance of 53.2 m. What was H? An obj
Serhud [2]

Answer:

H = 171.90 m

Explanation:

given data

distance = 53.2 m

height = H

to find out

height H

solution

we know height is here H = \frac{1}{2} gt^2    ......................1

here t is time and a is acceleration

so

we find t first

we know during time (t -1) s , it fall distance (H - 53.2) m

so equation of distance

H - 53.2 = \frac{1}{2} g (t-1)^2

H - 53.2 = \frac{1}{2} g (t^2-2t+1)

H - 53.2 = \frac{1}{2} gt^2-gt+\frac{1}{2} g     ................2

now subtract equation 2 from equation 1 so we get

H - (H - 53.2) =\frac{1}{2} gt^2- (\frac{1}{2} gt^2-gt+\frac{1}{2} g)

53.2 = gt - \frac{1}{2} g

53.2 = 9.81 t - \frac{1}{2} 9.8

t = 5.92 s

so from equation 1

H = \frac{1}{2} (9.81)5.92^2

H = 171.90 m

5 0
3 years ago
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

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Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

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= 26.8 x 26.8 / .335 x 9.8

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mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
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