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Anit [1.1K]
2 years ago
5

Pls help me fast and correct ​

Physics
1 answer:
bekas [8.4K]2 years ago
4 0

Answer:

A

Explanation:

due to position at height is the answer

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A typical oil control ring consists of _______ separate part(s).
azamat
<span>A. three</span><span>

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5 0
3 years ago
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A driver's foot presses with a steady force of 20N on a pedal in a car as shown.
azamat

Answer:

160N

Explanation:

Moments must be conserved - so.

20 * 0.4 = F * 0.05

F=\frac{20*0.4}{0.05} = 160

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4 years ago
A hungry hawk was preying on a lizard who was running northwards to get away from the low-flying hawk. If the lizard can run 8m
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Answer:

2m/s²

Explanation:

velocity = displacement (distance in a specified direction /time

8 0
3 years ago
A green truck is moving to the right. A red truck is moving to the left with a speed of 6 m/s. The mass of the red truck is 1,00
Contact [7]

Answer:

2 m/s

Explanation:

m_1 = Mass of red truck = 1000 kg

m_2 = Mass of green truck= 3000 kg

u_1 = Initial Velocity of red truck = 6 m/s

u_2 = Initial Velocity of green truck

v = Velocity with which they move together = 0

For elastic collision

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow m_1u_1 + m_2u_2 =0\\\Rightarrow u_2=-\frac{m_1u_1}{m_2}\\\Rightarrow u_2=-\frac{1000\times 6}{3000}\\\Rightarrow u_2=-2\ m/s

Velocity of the green truck is 2 m/s

8 0
3 years ago
A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a
bixtya [17]

Answer:

B_e = 2.72 \times 10^{-4} T

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

F = qvB

\frac{mv^2}{r} = qvB

now we have

r = \frac{mv}{qB}

since here radius of proton and electron will be same

so we will have

r_e = r_p

\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}

so we have

B_e = \frac{B_p m_e}{m_p}

given that

B_p = 0.50 T

m_e = 9.11 \times 10^{-31} kg

m_p = 1.67 \times 10^{-27} kg

so we have

B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}

B_e = 2.72 \times 10^{-4} T

4 0
3 years ago
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