Answer:
(1) Sure, the frequency is 1000 Hz.
Explanation:
Frequency = wave speed ÷ wave distance
wave speed = 100 m/s
wave distance = 10 cm = 10/100 = 0.1 m
Frequency = 100 ÷ 0.1 = 1000 Hz
Answer:
the time interval that an earth observer measures is 4 seconds
Explanation:
Given the data in the question;
speed of the spacecraft as it moves past the is 0.6 times the speed of light
we know that speed of light c = 3 × 10⁸ m/s
so speed of spacecraft v = 0.6 × c = 0.6c
time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds
Now, from time dilation;
t = Δt₀ / √( 1 - ( v² / c² ) )
t = Δt₀ / √( 1 - ( v/c )² )
we substitute
t = 3.2 / √( 1 - ( 0.6c / c )² )
t = 3.2 / √( 1 - ( 0.6 )² )
t = 3.2 / √( 1 - 0.36 )
t = 3.2 / √0.64
t = 3.2 / 0.8
t = 4 seconds
Therefore, the time interval that an earth observer measures is 4 seconds
Answer:
40 Hz
Explanation:
f = 1/T = 1 / 0.025 = 40 Hz
The phase and amplitude of rhythms in physiology and behavior are generated by circadian oscillators and entrained to the 24 h day by exposure to the light and dark cycle and feedback from the sleep wake cycle.the extent to which the phase and amplitude of multiple rhythms are similarly affected during altered timing of light exposure and the sleep wake cycle has not been fully characterized.
