2.0kg and the mass of sometimes makes it hard 2.8kg
Answer:
133.62 kmh.
Explanation:
Time provided = 3.25 hours.
Distance to be covered 300 km
Times spent in first 100 km = 1 hour
Time spent in next 43 km
= 43 / 40 = 1.075 hours
Total time spent = 2.075 hours
Total distance covered = 143 km
Distance remaining = 300 - 143
=157 km .
Time remaining = 3.25 - 2.075
= 1.175
Speed required = Distance remaining / time remaining
= 157 / 1.175
= 133.62 kmh.
Im pretty sure its A cuz is closer to the earth.
Answer:
Option C
Explanation:
Given:
- Clock speed f = 33 MHz
- The width of the bus w = 32 bits
Find:
what is the theoretical throughput in MiBytes?
Solution:
- First step is to convert the width of the bus to bytes as follows:
Bytes = 32 bits * (1 Bytes / 8 bits)
Bytes = 32 / 8
- Second step is to evaluate the time of the cycle:
Time period of clock T = 1 / f
Time period of clock T = 1 s / (33*10^6)
T = (1 / 33*10^6)
- Third step is to formulate the number of byte:
Number of byte = Bytes * T
= (32 / 8*33*10^6)
- Fourth step is to convert to Mi bytes:
Mibytes = Number of byte / 2^20
Mibytes = (32 / 8*33*10^6 * 2^20)
- The correct option is C