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777dan777 [17]
3 years ago
11

A 128 kbs point to point link is set up between Earth and a rover on Mars. Use the distance between Earth and Mars as 55Gm and t

hat data travels over the link at the speed of light, 3x108 m/s. A camera on the rover takes pictures of its surroundings and sends the pictures to Earth. The pictures are 5 Mb in size. How long would it take a picture to reach the Earth?
Physics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

Explanation:

Time Taken = Transmit + Propagation Delay

Propagation Delay = Distance/Speed of Light

= \frac{55\times 10^9}{3\times 10^8}\\\\= 183.334 seconds

Transmit = Size/Bandwidth

=\frac{5\times 10^6}{128\times 10^3}\\\\= 39.062 seconds

So, Total time = 183.334+39.062 = 222.396 seconds.

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FLUKE
Thepotemich [5.8K]

Answer:

cant understand anything

Explanation:

3 0
3 years ago
Under what condition is the instantaneous acceleration of a moving body equal to its average acceleration over time?
Rzqust [24]
If the acceleration is constant (negative or positive) the instantaneous acceleration cannot be

Average acceleration: [final velocity - initial velocity ] /Δ time

Instantaneous acceleration = d V / dt =slope of the velocity vs t graph

If acceleration is increasing, the slope of the curve at one moment will be higher than the average acceleration.

If acceleration is decreasing, the slope of the curve at one moment will be lower than the average acceleration.

If acceleration is constant, the acceleration at any moment is the same, then only at constant accelerations, the instantaneuos acceleration is the same than the average acceleration.

Constant zero acceleration is a particular case of constant acceleration, so at constant zero acceleration  the instantaneous accelerations is the same than the average acceleration: zero. But, it is not true that only at zero acceleration the instantaneous acceleration is equal than the average acceleration.

That is why the only true option and the answer  is the option D. only at constant accelerations.
3 0
4 years ago
An archer pulls a bow string 0.5 m. If the spring constant is 16,000 N/m, what is the energy stored in the bow string?
mars1129 [50]

2000J

Explanation:

Given parameters:

Extension = 0.5m

Spring constant = 16000N/m

Unknown:

Energy stored in the bow string = ?

Solution:

The energy stored in a bow string is an elastic potential energy.

It can be calculated using the expression below;

     Elastic energy = \frac{1}{2} K e²

Where k is the spring constant

            e is the extension

Input the parameters;

  Elastic energy = \frac{1}{2} K e²

                          =\frac{1}{2} x 16000 x 0.5²

                          = 2000J

learn more:

Potential energy brainly.com/question/10770261

#learnwithBrainly

3 0
4 years ago
What forms when two air masses meet and create weather?
Minchanka [31]
When two different air masses meet, a boundary is formed. the boundary between two air masses is called a front. weather at a front is usually cloudy and stormy. there at four different fronts: cold, warm, stationary, and occluded
4 0
3 years ago
Read 2 more answers
The graph illustrates the activity level of three common digestive enzymes, across a range of pH values. Which enzyme is likely
vaieri [72.5K]

Answer:

(A) Pepsin

Explanation:

From the graph it is clear that pepsin is the only enzyme which works in highly acidic condintion in the digestive system.

  • less than 7 the liquid is acidic
  • above 7 the liquid is basic
  • at 7 the liquid is neutral

It has an optimum pH of about 1.5 at which its activity level is 8.5 as shown in graph.

7 0
3 years ago
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