Well the answer is 207.2. You take the lowest sig figs that you are using which would be 2500= 2 sig figs. 207.2 rounded to 2 sig figs would be 210
Answer:
1) Maximun ammount of nitrogen gas:
2) Limiting reagent:
3) Ammount of excess reagent:
Explanation:
<u>The reaction </u>
Moles of nitrogen monoxide
Molecular weight:
Moles of hydrogen
Molecular weight:
Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess
1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted
2) <u>Limiting reagent</u>:
3) <u>Ammount of excess reagent</u>:
Answer:
(d) Heat flows from warmer to colder objects.
**wrong
answer is C
Answer:
the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins
Explanation:
The equilibrium constant of the reaction is 0.323.
Equilibrium constant:
It is expressed as the ratio of concentration of the products to the concentration of reactants. It is represented by K.
The relationship of K with G (Gibbs free energy) is expressed as:
G° = -RTlnK
Here R is the gas constant, T is the temperature.
Calculations:
Convert 25°C to K.
25°C = (25 + 273.15) K
= 298.15 K
Substitute the values in the above expression.
2.8 x 1000 J/mol = -8.314 J/mol.K x 298.15 K x ln(K)
lnK = 2800 J/mol/(-8.314 J/mol.K x 298.15 K)
lnK = -1.13
K = e^-1.13
= 0.323
Learn more about Gibbs free energy here:
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