Answer:
According to Avogadro's law, the volume of one mole of any gas at Standard Temperature and Pressure (STP = 273 K and 1 atm) is 22.4 L. Two important Gas Laws are required in order to convert the experimentally determined volume of hydrogen gas to that at STP. 1.
Explanation:
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Answer:
<h2>73.53 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question we have
We have the final answer as
<h3>73.53 mL</h3>
Hope this helps you
According to Henry's law, solubility of solution is directly proportional to partial pressure thus,
Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.
Putting the values in equation:
On rearranging,
Therefore, solubility will be 1.88 mg of 
gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.
Answer: The correct sequence for the series of event would be.
1. Igor's toe is being cut by the glass.
2. The wound surrounding the injury becomes infected with bacteria from Igor's foot.
3. Antibodies and circulating white blood cells stick to the bacteria creating a large complex in the lymph vessel.
4. The bacteria enter his lymph system and travel towards a lymph node.
5. The complex becomes trapped in a lymph node and is engulfed by a phagocyte.
6. The bacteria is destroyed.
Explanation:
Whenever there is any cut or wound in the body and body encounters invasion of the foreign materials it considers it as harmful pathogen.
These pathogens when enters the body it is considered as antigen, it then travels to the lymphatic system.
These bacterial complex is then killed by the phagocytes and digested by the body.
In this way the complex is killed and the bacteria is destroyed.
Answer:
CH3COOH would be more concentrated
Explanation:
The higher the concentration value, the more concentrated it is.
The relationship between concentration, moles and volume is given by the equation;
Concentration = No of moles / Volume
5.0 grams of HCOOH dissolved in 189 mL of water
Number of moles = Mass / Molar mass = 5 / 46.03 = 0.1086 mol
Concentration = 0.1086 / 0.189 = 0.5746 mol/L
1.5 moles of CH3COOH dissolved in twice as much water
Volume = 2 * 189 = 378 ml = 0.378 L
Concentration = 1.5 / 0.378 = 3.9683 mol/L
Comparing both concentration values;
CH3COOH would be more concentrated
