Answer:
uranium, caesium, potassium, beryllium,
Explanation:
0.091 moles are contained in 2.0 L of N2 at standard temperature and pressure.
Explanation:
Data given:
volume of the nitrogen gas = 2 litres
Standard temperature = 273 K
Standard pressure = 1 atm
number of moles =?
R (gas constant) = 0.08201 L atm/mole K
Assuming nitrogen to be an ideal gas at STP, we will use Ideal Gas law
PV = nRT
rearranging the equation to calculate number of moles:
PV = nRT
n = 
putting the values in the equation:
n = 
n = 0.091 moles
0.091 moles of nitrogen gas is contained in a container at STP.
Answer:
8.1433 g of XeF₆ are required.
Explanation:
Balanced chemical equation;
XeF₆ (s) + 3H₂ (g) → Xe (g) + 6HF (g)
Given data:
Volume of hydrogen = 0.579 L
Pressure = 4.46 atm
Temperature = 45 °C (45+273= 318 k)
Solution:
First of all we will calculate the moles of hydrogen
PV = nRT
n = PV/ RT
n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K
n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹
n = 0.0995 mol
Mass of hydrogen:
Mass = moles × molar mass
Mass = 0.0995 mol × 2.016 g/mol
Mass = 0.2006 g
Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.
H₂ : XeF₆
3 : 1
0.0995 : 1/3× 0.0995 = 0.0332 mol
Now we will calculate the mass of XeF₆.
Mass = moles × molar mass
Mass = 0.0332 mol × 245.28 g/mol
Mass = 8.1433 g
Answer:
dipole-dipole forces, ion-dipole forces, higher molar mass, hydrogen bonding, stronger intermolecular forces
Explanation:
<em>1. H₂S and H₂Se exhibit the following intermolecular forces: </em><em>dipole-dipole forces </em><em>and </em><em>ion-dipole forces</em><em>.</em> These molecules have a bent geometry, thus, a dipolar moment which makes them dipoles. When they are in the aqueous form they are weak electrolytes whose ions interact with the water dipoles
<em>2. Therefore, when comparing H₂S and H₂Se the one with a </em><em>higher molar mass</em><em> has a higher boiling point.</em> In this case, H₂Se has a higher boiling point than H₂S due to its higher molar mass.
<em>3. The strongest intermolecular force exhibited by H₂O is </em><em>hydrogen bonding</em><em>. </em>This is a specially strong dipole-dipole interaction in which the positive density charge on the hydrogens is attracted to the negative density charge on the oxygen.
<em>4. Therefore, when comparing H₂Se and H₂O the one with </em><em>stronger intermolecular forces</em><em> has a higher boiling point. </em>That's why the boiling point of H₂O is much higher than the boiling point of H₂Se.
