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Dima020 [189]
2 years ago
8

Compute g at a height of 7 RE above the surface of Earth (RE=6.4E+6m, ME=6.0E+24kg).

Physics
1 answer:
atroni [7]2 years ago
8 0

The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

<h3>What is acceleration due to gravity?</h3>

It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.

The acceleration due to gravity is related to the distance as

g =GM/R²

where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

Given is the height R = 7 x 6.4 x 10⁶ m and mass of  Earth M = 6 x 10²⁴ kg

Substitute the values into the expression to find the acceleration due to gravity.

g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²

g = 8.933 m/s²

Thus,  the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is  8.933 m/s².

Learn more about acceleration due to gravity.

brainly.com/question/13860566

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