Answer:
Explanation:
The pressure of the gas can be found out as follows
Gas law formula is as follows
PV = nRT
P = nRT / V
= 32.4 X 8.31 X ( 273 + 459.38 ) / 51 X 10⁻⁶
3866.45 X 10⁶ Pa.
The first change is isobaric therefore
V₁ / T₁ = V₂ / T₂
V₂ = V₁ X T₂/ T₁
= 51 X 10⁻⁶ X ( 855.6 +273) / (459.38 +273)
= 78 X 10⁻⁶
78 cm³
After the first operation , the pressure of the gas remains at
= 3866.45 X 10⁶ Pa.
Now volume of the gas changes from 78 cm³ to 25.3 cm³ isothermally so
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
= 3866.45 X 10⁶ X 78 / 25.3
= 11920 X 10⁶ . Pa
its the the first one u said
To develop this problem use the concept of the sum given pressure in the tank. At the bottom of the tank the pressure of this will be given by atmospheric pressure, the pressure given by the oil and the pressure by the water, that is to say that mathematically the pressure would be
<em>Note: Here the pressures are expressed in terms of density (), gravity (g) and thickness (t) or height (h). If we rearrange this equation to find the oil thickness we will have to,</em>
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Our values are given as,
Replacing we have that the thickness of the oil is:
Therefore the thick of the oil is 0.5947m
Answer:
The ball has an initial linear kinetic energy and initial rotational kinetic energy which can both be converted into gravitational potential energy. Therefore the hill with friction will let the ball reach higher.
Explanation:
The ball has an initial linear kinetic energy and initial rotational kinetic energy which can both be converted into gravitational potential energy. Therefore the hill with friction will let the ball reach higher.
This is because:
If we consider the ball initially at rest on a frictionless surface and a force is exerted through the centre of mass of the ball, it will slide across the surface with no rotation, and thus, there will only be translational motion.
Now, if there is friction and force is again applied to the stationary ball, the frictional force will act in the opposite direction to the force but at the edge of the ball that rests on the ground. This friction generates a torque on the ball which starts the rotation.
Therefore, static friction is infact necessary for a ball to begin rolling.
Now, from the top of the ball, it will move at a speed 2v, while the centre of mass of the ball will move at a speed v and lastly, the bottom edge of the ball will instantaneously be at rest. So as the edge touching the ground is stationary, it experiences no friction.
So friction is necessary for a ball to start rolling but once the rolling condition has been met the ball experiences no friction.
friction make non moving objects starts to move
there are different types of force which may help them to move