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2 years ago

Please Help - Complete the table

Chemistry

1 answer:

mario62 [17]2 years ago

7 0

Answer:

Proteins

Elements: C, H, O, N, and some S

Monomer: amino acids

Functions: catalyzing chemical reactions, synthesizing and repairing DNA, structural support, transporting materials across the cell

Examples: hemoglobin, actin and myosin, albumin, keratin

Carbohydrates

Elements: C, H, O

Monomer: monosaccharides

Functions: cellular identity, source of energy, storage of energy, structural support, cell signaling, make ATP, convert solar energy

Examples: glucose, starch, glycogen, peptidoglycan, cellulose, chitin

Nucleic Acids

Elements: C, H, O, N, P

Monomer: nucleotides

Functions: storage and expression of genetic information, transmission of genetic code required for making proteins

Examples: DNA, RNA

Lipids

Elements: C, H, O, and some P and N

Monomer: fatty acids

Functions: energy storage, cell structure, insulation and protection, regulating and signaling, digestion

Examples: steroids (cholesterol), waxes, fats and oils, phospholipids

Hope that helps.

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The following chemical equations are organized by reaction type. You must balance each reaction, and show your work

sukhopar [10]

Answer:

lets be honest

Explanation:

no one knows and this is worthless to answer for the worth of 5 points

4 0

2 years ago

90 POINTSSSS!!!

Katarina [22]

Answer:

$\large \boxed{\text{-2043.96 kJ/mol}}$

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)

Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

$\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}$

(b)Total enthalpies of reactants and products

$\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\= \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}$

ΔᵣH° is negative, so the reaction is exothermic.

5 0

2 years ago

The molar mass of an element is the mass of one

allochka39001 [22]

Answer:

The molar mass of an element is the mass of one mole of atoms of the element.

Explanation:

The molar mass of an element is its atomic mass, i.e. the mass in grams of one mole of atoms of the element.

Remember 1 mol is approximately 6.022 × 10²³.

So, 1 mol of atoms is 6.022 × 10²³ atoms.

The molar mass is an average: it is the weighted average mass of the natural isotopes of the element, taking into account their relative abundance.

For example, the molar mass or atomic mass of carbon is 12,0107 g/mol, instead of 12.0000, becasue carbon exists in several forms (isotopes), and so the weighted average is not a whole number.

7 0

2 years ago

33. Why does Fluorine exert a stronger pull than Chlorine on the valence electrons of another

mariarad [96]

Answer:

Fluorine is much more reactive than chlorine (despite the lower electron affinity) because the energy released in other steps in its reactions more than makes up for the lower amount of energy released as electron affinity.

Explanation:

7 0

2 years ago

How much ice (in grams) would have to melt to lower the temperature of 354 ml of water from 26 ?c to 6 ?c? (assume the density o

Anit [1.1K]

Heat gained in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

When two objects are in contact, it should be that the heat lost is equal to what is gained by the other. From this, we can calculate things. We do as follows:

Heat gained = Heat lost
mC(T2-T1) = - mC(T2-T1)

C(liquid water) = 4.18 J/gC
C(ice) = 2.11 J/gC

(354 mL)(1.0 g/mL)(4.18 J/gC)(26 C - 6 C) = m(2.11 J/gC)(6 - 0C) 
m = 2337.63 g of ice

3 0

3 years ago