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3 years ago

Please Help - Complete the table

Chemistry

1 answer:

mario62 [17]3 years ago

7 0

Answer:

Proteins

Elements: C, H, O, N, and some S

Monomer: amino acids

Functions: catalyzing chemical reactions, synthesizing and repairing DNA, structural support, transporting materials across the cell

Examples: hemoglobin, actin and myosin, albumin, keratin

Carbohydrates

Elements: C, H, O

Monomer: monosaccharides

Functions: cellular identity, source of energy, storage of energy, structural support, cell signaling, make ATP, convert solar energy

Examples: glucose, starch, glycogen, peptidoglycan, cellulose, chitin

Nucleic Acids

Elements: C, H, O, N, P

Monomer: nucleotides

Functions: storage and expression of genetic information, transmission of genetic code required for making proteins

Examples: DNA, RNA

Lipids

Elements: C, H, O, and some P and N

Monomer: fatty acids

Functions: energy storage, cell structure, insulation and protection, regulating and signaling, digestion

Examples: steroids (cholesterol), waxes, fats and oils, phospholipids

Hope that helps.

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3 years ago

Read 2 more answers

Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a

s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is $1.43\times 10^{-7} mol/L$ .

Explanation:

Partial pressure of the $O_2$ gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

$p_{o_2}=K_H\times\chi_{O_2}$

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

$0.0013=34860 bar\times \chi_{O_2}$

$\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}$

Let the number of moles of $O_2$ gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L $n_w=\frac{1000 g}{18 g/mol}=55.55 mol$

$\chi_{O_2}=\frac{n}{n+n_w}$

$2.56\times 10^{-5}=\frac{n}{n+55.55}$

$n=1.43\times 10^{-7} moles$

$Molarity=\frac{\text{Moles of}O_2}{Volume}$

Molar concentration of oxygen gas in 1 L of water:

$=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L$

The molar concentration of oxygen gas in water is $1.43\times 10^{-7} mol/L$ .

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4 years ago

I've asked before and gotten spammed hopefully I won't get spammed this time please help me with this someone. pls help anyonw

elena55 [62]

Answer:

See below!

Explanation:

A. The picture of the graph is attached. You can tell the amount of protons in an element by looking at the periodic table. The elements are ordered by the number of protons in an element.

B. Carbon and silicon are at the peaks of the chart. The peak is the highest point in a graph.

C. The elements belong to the non-metal group.

D. The halogens are non-metals, and their vapors are colorless.

The halogens are toxic to humans.

Halogen molecules are made of two atoms; they are diatomic.

Halogens react with non-metals to form crystalline compounds that are salts.

The halogens get less reactive going down the group on the periodic table.

Halogens can bleach vegetable dyes and kill bacteria.

E. The picture of the table is attached. To figure which numbers to put where, you need to pay attention to the other numbers. The halogens follow a trend with each of these properties. You have to put in the numbers that fit in among the other numbers.

3 0

3 years ago

How much heat is absorbed when 63.7 g H2O(l) at 100 degrees Celsius and 101.3kPa is converted to steam at 100

Alona [7]

Answer:

Q = 143,921 J = 143.9 kJ.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the absorbed heat by considering this is a process involving sensible heat associated to the vaporization of water, which is isothermic and isobaric; and thus, the heat of vaporization of water, with a value of about 2259.36 J/g, is used as shown below:

$Q=m*\Delta _{vap}H$

Thus, we plug in the mass and the aforementioned heat of vaporization of water to obtain the following:

$Q=63.7g*2259.36J/g\\\\Q=143,921J=143.9kJ$

Regards!

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3 years ago