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sertanlavr [38]
2 years ago
13

Draw two lewis structures for a compound with the formula c4h10. No atom bears a charge, and all carbon atoms have complete octe

ts. Include all hydrogen atoms.
Chemistry
1 answer:
DIA [1.3K]2 years ago
4 0

Answer:

See pictures!

Explanation:

Here is a drawing of butane (C4H10); labeled #1. An isomer of butane will also have the chemical formula C4H10 but is depicted different geometrically. I labeled this one #2.

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What is ionization energy? What is fist ionization energy?
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The ionization energy is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.The first ionisation energy is the energy required to remove one mole of the most loosely held electrons from one mole of gaseous atoms to produce 1 mole of gaseous ions each with a charge of 1+. I hope this helps :3
8 0
3 years ago
Which of the following statements is true with regard to transverse and longitudinal waves?
Ipatiy [6.2K]

Answer:

D (The last answer)

Explanation:

In a transverse wave, particles oscillate perpendicular to the direction of wave motion.

In a longitudinal wave, the oscillations of particles are parallel to the direction of propagation.

5 0
3 years ago
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Atomic size of inert gases do not affect you inertness why​
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Answer:

Because your body has built-in resistance to certain gases, no matter the size of the gas cloud.

That is why we are able to stay non-inert to these types of gases, like Carbon dioxide.

6 0
2 years ago
Which sample contains a total of 3.0 x 10^23 molecules?
belka [17]
Given that 1 mole contains 6.02x10^23 molecules, 3.0x10^23 is just around half a mole. Then we check the number of moles for each choice:

A. This is approximately half a mole, since the molar mass of Br2 is 159.8 g/mol.
B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
D. Li has a molar mass of around 6.97 g/mol, so this is around 2 moles.

Therefore the only choice that fits is A. 80 g of Br2.
3 0
3 years ago
Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
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