Draw two lewis structures for a compound with the formula c4h10. No atom bears a charge, and all carbon atoms have complete octe
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<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L
<u>Explanation:</u>
We are given:
Moles of carbon dioxide = 4.76 moles
<u>At STP:</u>
1 mole of a gas occupies a volume of 22.4 Liters
So, for 4.76 moles of carbon dioxide gas will occupy a volume of =
Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L
The chart with the information to answer this question may be found in other Brainly's link, so I attach it now.
Answer:
- Z
Explanation:
To facilitate the accompaniment of the reasoning, I copy the data here:
Object Motion
X 3 units left, 3 units right
Y 6 units right, 18 units right
W 8 units left, 24 units right
Z 16 units right, 8 units left
The <em>distance</em> is the scalar magnitude that indicates the total length of the path traveled.
The <em>displacement</em> is the vector that indicates how far the end point and the initial point are.
In order to calculate the distance, the displacement and the ratio r = distance/displacement, to check which object has a distance that is three times as great as its displacement, i.e. r = 3, we use this new chart:
Object Motion Distance Displacement ratio
X 3 units left, 3 units right 3 + 3 = 6 3 - 3 = 0 ∞
Y 6 units right, 18 units right 6 + 18 = 24 6 + 18 = 24 1
W 8 units left, 24 units right 8 + 24 = 32 -8 + 24 = 16 2
Z 16 units right, 8 units left 16 + 8 = 24 16 - 8 = 8 3
The ratios were calculated dividing the distance by the displacement: distance / displacement.
For the object Z, that was 24 / 8 = 3. Thus, the object that has a distance that is three times as great as its displacement is the object Z.
Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.
The four isomers of the compound is shown in the figure.
In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.
The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.
In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.
The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.
Thus the four isomers of the compound is shown.
