Question

A cyclist accelerates from 0 m/s to 8 m/s in 3 seconds. What is her acceleration? Is the acceleration higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds? How do you know?

Answer 1

Answer:

Acceleration of one cyclist=$2.67m/s^2$

Yes, the acceleration is higher of another cyclist who accelerates from 0 to 30 m/s in 8 seconds.

Explanation:

We are given that

Initial velocity of one cyclist, u=0 m/s

Final velocity of one cyclist, v=8m/s

Time, t=3 s

Initial velocity of another cyclist, u'=0

Final velocity of another cyclist, v'=30m/s

Time, t'=8 s

We know that

Acceleration, $a=\frac{v-u}{t}$

Using the formula

$a=\frac{8-0}{3}=\frac{8}{3}=2.67m/s^2$

Acceleration of one cyclist=$2.67m/s^2$

Acceleration of another cyclist, a'=$\frac{30-0}{8}m/s^2$

Acceleration of another cyclist, a'=$3.75m/s^2$

Yes, the acceleration of another cyclist is higher than the cyclist which accelerates from 0m/s to 8m/s.