Answer:
The answer is c( to send signals to control the body)
Answer:
Explanation: I also have a question if anyone can help in chem please
Answer: The rate of appearance of
is 
Explanation:
Rate of a reaction is defined as the rate of change of concentration per unit time.
Thus for reaction:

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
![Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}](https://tex.z-dn.net/?f=Rate%3D-%5Cfrac%7B1d%5BI%5E-%5D%7D%7B5dt%7D%3D%2B%5Cfrac%7Bd%5BI_2%5D%7D%7B3dt%7D)
Given:
= 
![+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls](https://tex.z-dn.net/?f=%2B%5Cfrac%7Bd%5BI_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B3d%5BI%5E-%5D%7D%7B5dt%7D%3D-%5Cfrac%7B3%7D%7B5%7D%5Ctimes%202.4%5Ctimes%2010%5E%7B-3%7Dmol%2FLs%3D1.44%5Ctimes%2010%5E%7B-3%7Dmol%2FLs)
The rate of appearance of
is 
Answer:
a.
![rate_{NH_3}=\frac{2d[NH_3]}{dt}](https://tex.z-dn.net/?f=rate_%7BNH_3%7D%3D%5Cfrac%7B2d%5BNH_3%5D%7D%7Bdt%7D)
b.
![rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}](https://tex.z-dn.net/?f=rate_%7BN_2%7D%3D%5Cfrac%7B-1d%5BN_2%5D%7D%7Bdt%7D%20%5C%5C%5C%5Crate_%7BH_2%7D%3D%5Cfrac%7B-3d%5BH_2%5D%7D%7Bdt%7D)
Explanation:
Hello there!
In this case, according to the law of rate proportions, it is possible to write the the rates of reaction for the formation of NH3 and the disappearance of the N2 and H2, by considering that the coefficient in the reaction for NH3 is +2 and those of N2 and H2, -1 and -3 respectively. Moreover, we set up these equations as derivatives as shown below:
a.
![rate_{NH_3}=\frac{2d[NH_3]}{dt}](https://tex.z-dn.net/?f=rate_%7BNH_3%7D%3D%5Cfrac%7B2d%5BNH_3%5D%7D%7Bdt%7D)
b.
![rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}](https://tex.z-dn.net/?f=rate_%7BN_2%7D%3D%5Cfrac%7B-1d%5BN_2%5D%7D%7Bdt%7D%20%5C%5C%5C%5Crate_%7BH_2%7D%3D%5Cfrac%7B-3d%5BH_2%5D%7D%7Bdt%7D)
Best regards!