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stira [4]
2 years ago
6

Burning a piece of wood in fire can be best described as a

Chemistry
1 answer:
inna [77]2 years ago
7 0

Answer:

Chemical Change

Explanation:

A chemical change is when something is turned into a new substances.

In this example the wood is being turned into ash.

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just olya [345]

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D) Covalent Bonds

Explanation:

Quizlet says so

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Waves crash on a beach one after another. Why doesn't water pile up on the beach
Klio2033 [76]

sand

Explanation:

it is absorbing it

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3 years ago
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What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?
inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case:

  • Molarity: 1.56 M= 1.56 \frac{moles}{liter}
  • Number of moles of calcium chlorine= ?
  • Volume= 2.657 liters

Replacing:

1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

  • Ca: 40 g/mole
  • Cl: 35.45 g/mole

Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass=\frac{4.14 moles*110.9g}{1 mole}

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

3 0
2 years ago
A voltaic cell is constructed using the following half-reactions: Ag+(aq) + e- ---&gt; Ag(s) EoAg+ = +0.80 V Cu2+(aq) + 2e- ---&
Anton [14]
- Standard reduction potential of Ag/Ag⁺ is 0.80 v and that of Cu⁺²(aq)/Cu⁰ is +0.34 V.
- The couple with a greater value of standard reduction potential will oxidize the reduced form of the other couple.
Ag⁺ will be reduced to Ag(s) and Cu⁰ will be oxidized to Cu²⁺
Anode reaction: Cu⁰(s) →  Cu²⁺ + 2 e⁻     E⁰ = +0.34 V
Cathode reaction: Ag⁺(aq) + e → Ag(s)     E⁰ = +0.80 V 
Cell reaction: Cu⁰(s) + 2 Ag⁺(aq) → Cu⁺²(aq) + 2 Ag⁰(s)
E⁰ cell = E⁰ cathode + E⁰ anode
            = 0.80 + (-0.34) = + 0.46 V
   
5 0
2 years ago
Question # 10
satela [25.4K]
The answer should be D, cells can only create an identical copy of the original cell.
3 0
3 years ago
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