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stira [4]
2 years ago
6

Burning a piece of wood in fire can be best described as a

Chemistry
1 answer:
inna [77]2 years ago
7 0

Answer:

Chemical Change

Explanation:

A chemical change is when something is turned into a new substances.

In this example the wood is being turned into ash.

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The photo shows nervous tissue.
Nikolay [14]

Answer:

The answer is c( to send signals to control the body)

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3 years ago
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At what temperature does ice melt at 101kPa?
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Answer:

Explanation: I also have a question if anyone can help in chem please

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2 years ago
For the reaction IO3–(aq) + 5 I–(aq) + 6 H+(aq) → 3 I2(aq) + 3 H2O(l) the rate of disappearance of I–(aq) at a particular time a
scoray [572]

Answer: The rate of appearance of I_2(aq) is 1.44\times 10^{-3}mol/Ls

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

IO_3^-(aq)+5I^-(aq)+6H^+(aq)\rightarrow 3I_2(aq)+3H_2O(l)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}

Given: -\frac{d[I^-]}{dt}] = 2.4\times 10^{-3}mol/Ls

+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls

The rate of appearance of I_2(aq) is 1.44\times 10^{-3}mol/Ls

6 0
3 years ago
How many moles of Na are in 11.9 grams of Na
hram777 [196]

Answer:

sdgas

Explanation:

as dggsda

8 0
2 years ago
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The reaction for the formation of ammonia is given a
Leni [432]

Answer:

a.

rate_{NH_3}=\frac{2d[NH_3]}{dt}

b.

rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}

Explanation:

Hello there!

In this case, according to the law of rate proportions, it is possible to write the the rates of reaction for the formation of NH3 and the disappearance of the N2 and H2, by considering that the coefficient in the reaction for NH3 is +2 and those of N2 and H2, -1 and -3 respectively. Moreover, we set up these equations as derivatives as shown below:

a.

rate_{NH_3}=\frac{2d[NH_3]}{dt}

b.

rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}

Best regards!

5 0
2 years ago
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