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2 years ago

10 points

Chemistry

1 answer:

Oduvanchick [21]2 years ago

7 0

Answer:

table C will be the correct answer

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The molecular formula of a compound is C7H14O7. what is the empirical formula

nata0808 [166]

Empirical formula is the simplest way the molecular formula can be wrote so here 7 goes into all of these so it would be CH2O

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2 years ago

The symbol for the hydroxide ion is _____. H + H 3 O - H(OH) OH -

dimulka [17.4K]

The symbol for the hydroxide ion is OH-

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3 years ago

Read 2 more answers

Explain atoms contain positively charge protons and negatively charge electrons. why does an ordinary atom have no charge?

tatiyna

An ordinary atom is balanced for instance, lithium has 3 protons and 3 electrons the positively charged proton cancels the negatively charged electron.

THINK math plus 3 and negative 3 = 0 neutral

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2 years ago

Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4

Aleksandr [31]

The concentration of hydroxide ion is 5 $\times$ 10^ − 14 M.

Explanation:

Consider the equilibrium of this acid's dissociation,

H C l O 4 ⇌ H + + C l O 4 -

Moreover, let's assume that H C l O 4 is a strong acid and will fully dissociate.

Hence,

[ H + ] = 0.20 M

Now, recall,

K w = [ H + ] [ O H − ] = 1.0 $\times$ 10 ^− 14

Hence,

⇒ [ O H − ] = K w / [ H + ] = 5 $\times$ 10^ − 14 M.

7 0

3 years ago

Phosphine, an extremely poisonous and highly reactive gas, will react with oxygen to form tetraphosphorus decoxide and water, as

erica [24]

Answer: The amount of $P_4O_{10}$ formed is 469.8 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of phosphine = 225 g

Molar mass of phosphine = 34 g/mol

Putting values in equation 1, we get:

$\text{Moles of phosphine}=\frac{225g}{34g/mol}=6.62mol$

The given chemical reaction follows:

$4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)$

Assuming that oxygen gas is present in excess, it is considered as an excess reagent.

Phosphine is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

4 moles of phosphine produces 1 mole of $P_4O_{10}$

So, 6.62 moles of phosphine will produce = $\frac{1}{4}\times 6.62=1.655mol$ of $P_4O_{10}$

Now, calculating the mass of $P_4O_{10}$ by using equation 1:

Molar mass of $P_4O_{10}$ = 283.9 g/mol

Moles of $P_4O_{10}$ = 1.655 moles

Putting values in equation 1, we get:

$1.655mol=\frac{\text{Mass of }P_4O_{10}}{283.9g/mol}\\\\\text{Mass of }P_4O_{10}=(1.655mol\times 283.9g/mol)=469.8g$

Hence, the amount of $P_4O_{10}$ formed is 469.8 grams.

8 0

2 years ago