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Nana76 [90]
2 years ago
8

10 points

Chemistry
1 answer:
Oduvanchick [21]2 years ago
7 0

Answer:

table C will be the correct answer

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Why is water a polar molecule? ? Why is water a polar molecule? ? 4 following 6 answers 6 Report Abuse Are you sure you want to
anyanavicka [17]
In a covalent bond one atom can attract the shared electrons more strongly than the other atom can. Water or H2O has a covalent bond whose Oxygen atoms attract more electrons that its Hydrogen atom. Since electrons have a negative charge, the Oxygen atom has a partial negative charge and the Hydrogen atom has a partial positive charge. These partial charges are what make water a polar molecule.marrit <span>· 2 years ago</span>
5 0
3 years ago
17 points Pls helpppppopppp
pentagon [3]

Answer:

Lipids

Explanation:

Lipids perform many different functions in a cell. Cells store energy for long-term use in the form of lipids called fats. Lipids also provide insulated from the environment for plants and animals

8 0
3 years ago
Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electr
Alecsey [184]

Answer:

The wavelength of the emitted photon will be approximately 655 nm, which corresponds to the visible spectrum.

Explanation:

In order to answer this question, we need to recall Bohr's formula for the energy of each of the orbitals in the hydrogen atom:

E_{n} = -\frac{m_{e}e^{4}}{2(4\pi\epsilon_{0})^2\hbar^{2}}\frac{1}{n^2} = E_{1}\frac{1}{n^{2}}, where:

[tex]m_{e}[tex] = electron mass

e = electron charge

[tex]\epsilon_{0}[tex] = vacuum permittivity

[tex]\hbar[tex] = Planck's constant over 2pi

n = quantum number

[tex]E_{1}[tex] = hydrogen's ground state = -13.6 eV

Therefore, the energy of the emitted photon is given by the difference of the energy in the 3d orbital minus the energy in the 2nd orbital:

[tex]E_{3} - E_{2} = -13.6 eV(\frac{1}{3^{2}} - \frac{1}{2^{2}})=1.89 eV[tex]

Now, knowing the energy of the photon, we can calculate its wavelength using the equation:

[tex]E = \frac{hc}{\lambda}[tex], where:

E = Photon's energy

h = Planck's constant

c = speed of light in vacuum

[tex]\lambda[tex] = wavelength

Solving for [tex]\lambda[tex] and substituting the required values:

[tex]\lambda = \frac{hc}{E} = \frac{1.239 eV\mu m}{1.89 eV}=0.655\mu m = 655 nm[tex], which correspond to the visible spectrum (The visible spectrum includes wavelengths between 400 nm and 750 nm).

5 0
3 years ago
Mass of 0.432 moles of C8H9O4?
Fiesta28 [93]
Find one mole
8 C = 8 * 12 = 96
9 H = 1 * 9 = 9
4 O = 4 *16 = 64
Total = 169 

1 mol = 169 grams.
0.432 mol = x

1/0.432 = 169/x
x = 0.432 * 169
x = 73.0 grams
7 0
3 years ago
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Rpd pls ii test :)<br><br> tot ce se afla in poza
mamaluj [8]

Answer:

Sorry mate! I can't understand this language...

4 0
3 years ago
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