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Sliva [168]
3 years ago
10

A shuttle on Earth has a mass of 4.5 E 5 kg. Compare its weight on Earth to its weight while in orbit at a height of 6.3 E 5 met

ers above the surface of the Earth. Approximately what percent of its weight does the space shuttle retain?
11%
44%
83%
91%
Physics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

83%

Explanation:

On the surface, the weight is:

W = GMm / R²

where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.

In orbit, the weight is:

w = GMm / (R+h)²

where h is the height of the shuttle above the surface of the Earth.

The ratio is:

w/W = R² / (R+h)²

w/W = (R / (R+h))²

Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:

w/W = (6.4×10⁶ / 7.03×10⁶)²

w/W = 0.83

The shuttle in orbit retains 83% of its weight on Earth.

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0.61°

Explanation:

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3 0
3 years ago
A 6.7kg object moves with a velocity of 8m/s. What's its kinetic energy?
Snezhnost [94]

Given parameters:

Mass of object = 6.7kg

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Unknown parameter:

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Energy is defined as the ability to do work. There are two forms of energy;

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Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest.

Kinetic energy is mathematically expressed as;

             Kinetic energy  = \frac{1}{2} m v^{2}

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Since we have been given both mass and velocity, input the parameter to solve for the unknown;

            Kinetic energy  = \frac{1}{2} x 6.7 x 8²   = 214.4‬J

So the kinetic energy of the body is  214.4‬J

3 0
3 years ago
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