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umka2103 [35]
3 years ago
10

Describe the magnetic field lines around a bar magnet

Physics
2 answers:
Sophie [7]3 years ago
6 0
The lines can be traced out with a compass. The needle is like a permanent magnet and the north indicator is the north end of a magnet.
oee [108]3 years ago
4 0

Answer:

They point away from the north pole and toward the south pole

Explanation:

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Apart from physical factors, what other environmental factors are in your environment?
lora16 [44]

Answer:

Explanation:

Factors which affects and impacts our environment may include water, sunlight, buildings and so many other. The factors which can touched are called the physical factors. The physical factirs include buildings, humans and so on. Other factirs which aren't physical inckide the the effects posed to the environment t by biological and chemical factirs which may include, the impacts in sunlight and Rainfall, the pH and so on.

5 0
3 years ago
When current first leaves the battery, how much voltage does it have
rjkz [21]

Answer:

depends on the voltage of battery

Explanation:

for example if you connect a battery of 6V,6V will be  provided

8 0
3 years ago
How did the work of Dmitri Mendeleev differ from that of John Newlands in the development of the periodic table?
Sonja [21]
B.

Both recognized that the elements have repeating properties but Mendeleev realized that there are elements yet to be discovered while Newlands tried to fit the known elements together.
3 0
3 years ago
Read 2 more answers
Astronomy question, <br> what keeps supernova explosions from being seen?
kirill115 [55]

a star that suddenly increases greatly in brightness because of a catastrophic explosion that ejects most of its mass.
4 0
3 years ago
You hang different masses M from the lower end of a vertical spring and measure the period T for each value of M. You use Excel
Svetradugi [14.3K]

Answer:

a)693.821N/m

b)17.5g

Explanation:

We the Period T we can find the constant k,

That is

T = 2 \pi \sqrt{\frac{m}{k}}

squaring on both sides,

T^2=\frac{4\pi^2}{k}M +\frac{4\pi^2}{k}m_{spring}

where,

M=hanging mass, m = spring mass,

k =spring constant

T =time period

a) So for the equation we can compare, that is,

y=T^2=0.0569x+0.0010

the hanging mass M is x here, so comparing the equation we know that

\frac{4\pi^2}{k}=0.0569\\k= \frac{4\pi^2}{0.0569}\\k=693.821N/m

b) In order to find the mass of the spring we make similar process, so comparing,

\frac{4\pi^2}{k}m =0.001\\m=\frac{0.004k}{4\pi^2} =\frac{0.001*693.821}{4\pi^2}\\m=0.0175kg\\m=17.5g

3 0
3 years ago
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