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3 years ago

Describe the magnetic field lines around a bar magnet

2 answers:

6 0

The lines can be traced out with a compass. The needle is like a permanent magnet and the north indicator is the north end of a magnet.

oee [108]3 years ago

4 0

Answer:

They point away from the north pole and toward the south pole

Explanation:

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A lacrosse ball that is thrown straight upwards reaches a maximum height of 4.5 m. At what initial velocity was it thrown? (note

shtirl [24]

Answer:

The initial velocity was 9.39 m/s

Explanation:

Lets explain how to solve the problem

The ball is thrown straight upward with initial velocity u

The ball reaches a maximum height of 4.5 m

At the maximum height velocity v = 0

The acceleration of gravity is -9.8 m/s²

We need to find the initial velocity

The best rule to find the initial velocity is v² = u² + 2ah, where v is

the final velocity, u is the initial velocity, a is the acceleration of

gravity and h is the height

⇒ v = 0 , h = 4.5 m , a = -9.8 m/s²

⇒ 0 = u² + 2(-9.8)(4.5)

⇒ 0 = u² - 88.2

Add 88.2 to both sides

⇒ 88.2 = u²

Take square root for both sides

⇒ u = 9.39 m/s

The initial velocity was 9.39 m/s

5 0

3 years ago

how much force is needed to cause a 15 kilogram bike to accelerate at a rate of 10 meters per second?

egoroff_w [7]

F = m*a, mass times acceleration.

F = 15*10 = 150 N

8 0

3 years ago

Read 2 more answers

A: hydrogen and hydrogen b: copper and copper c: copper and oxygen Rank the above bonds in terms of increasing bond strength. Ch

pashok25 [27]

Answer: Copper and oxygen

Explanation:

Copper and oxygen shares the ionic bond. As we know that ionic bond is the most strongest bond. Here is the order:

Hydrogen bond< Metallic bond< Ionic bond.

That means order in terms of increasing bond strength is :

Hydrogen and hydrogen< Copper and copper< Copper and oxygen.

5 0

3 years ago

Convert 3.5revolutions to radians.

olga55 [171]

As we know that

$1 revolution = 2\pi radian$

now we know that

$3.5 revolution = 3.5 rev\times \frac{2\pi rad}{1 rev}$

$3.5 rev = 21.98 rad$

so it is 21.98 radian

8 0

3 years ago

Read 2 more answers

A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The

mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

$v = v_{o}+a\cdot t$

Where:

$v_{o}$ - Initial velocity, measured in meters per second.

$v$ - Final velocity, measured in meters per second.

$a$ - Acceleration, measured in meters per square second.

$t$ - Time, measured in seconds.

Now, we clear acceleration within expression:

$a = \frac{v-v_{o}}{t}$

Initial and final velocities are now converted from kilometers per hour into meters per second:

$v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v_{o} = 30\,\frac{m}{s}$

$v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)$

$v = 37.5\,\frac{m}{s}$

If we know that $t = 3.5\,s$ , then, the average acceleration of the car is:

$a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}$

$a = 2.143\,\frac{m}{s^{2}}$

The average acceleration of the car is 2.143 meters per square second.

8 0

3 years ago