AnswerWhat Are the Classifications of Burns? Burns are classified as first-, second-, or third-degree, depending on how deep and severe they penetrate the skin's surface. First-degree burns affect only the epidermis, or outer layer of skin. The burn site is red, painful, dry, and with no blisters.
Explanation:
We are given a CSP with only binary can concentrate assume we run backtrackingSearch with ARC
Answer:
The difference of head in the level of reservoir is 0.23 m.
Explanation:
For pipe 1
For pipe 2
Q=2.8 l/s
We know that Q=AV
head loss (h)
Now putting the all values
So h=0.23 m
So the difference of head in the level of reservoir is 0.23 m.
Answer:
Explanation:
The Turnaround time is the amount of time that elapses between the job arriving and completing. We assume that all jobs arrive at time 0, the turnaround time will simply be the time that they complete.
Round Robin:
we assume that the time quantum of the scheduler is 1 second.The table below gives a break down of which jobs will be processed during each time quantum. A asterisk(*) indicates that the job completes during that quantum.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
A B C D E A B C* D E A B D E A B D* E A B E A B* E A E A E* A A
C* = 8
D*=17
B*=23
E*=28
AVERAGE TURNAROUND = (8+17+23+28+30)/5 =106/5 = 21.2 MINUTES
B) PRIORITY SCHEDULING:
1-6 7-14 15-24 25-26 27-30
B E A C D
AVERAGETURNAROUND =(6+14+24+26+30)/5 = 100/5 = 20 MINUTES.
C)FCFS
1-10 11-16 17-18 19-22 23-30
A B C D E
AVERAGE TURNAROUND =(10+16+18+22+30)/5 = 96/5=19.2 MINTUES
D)SJF
1-2 3-6 7-12 13-20 21-30
C D B E A
AVERAGE TURNAROUND - (2+6+12+20+30)/5 =70/5 =14 MINUTES.
Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem