What is future active and future passive and future perfect active
1 answer:
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For the given problem it is necessary to recap the concepts about Power, that is, is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time.
The equation for power can be written as
Where,
F= Net Force
V =Velocity
By the second newton law, force can be:
F = mg
Where m means the mass and g the gravity acceleration.
We can also write the equation as,
P = mgv
Replacing the values
P = 700*9.8*25
P = 17.15kW
Tenemos unidades en dos sistemas diferentes, por lo que convertimos los HP a Sistema internacional y tenemos que
1hp = 0.746kW
Then the fraction is,
Therefore the fraction of the engine power is being used to make the airplane climb is 22.984%
Answer:
Explanation:
Given
Required
Convert to standard form
From laws of indices
So, is equivalent to
Hence, the standard form of is
Image of wheel is missing, so i attached it.
Answer:
ω = 14.95 rad/s
Explanation:
We are given;
Mass of wheel; m = 20kg
T = 20 N
k_o = 0.3 m
Since the wheel starts from rest, T1 = 0.
The mass moment of inertia of the wheel about point O is;
I_o = m(k_o)²
I_o = 20 * (0.3)²
I_o = 1.8 kg.m²
So, T2 = ½•I_o•ω²
T2 = ½ × 1.8 × ω²
T2 = 0.9ω²
Looking at the image of the wheel, it's clear that only T does the work.
Thus, distance is;
s_t = θr
Since 4 revolutions,
s_t = 4(2π) × 0.4
s_t = 3.2π
So, Energy expended = Force x Distance
Wt = T x s_t = 20 × 3.2π = 64π J
Using principle of work-energy, we have;
T1 + W = T2
Plugging in the relevant values, we have;
0 + 64π = 0.9ω²
0.9ω² = 64π
ω² = 64π/0.9
ω = √64π/0.9
ω = 14.95 rad/s
