A student prepared a saturated solution of cacro4 and found that when 156 ml of the solution was evaporated, 0. 649 g of cacro4

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1 year ago

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was left behind. What is the value of ksp for this salt?

1 answer:

labwork [276] · Answer 1 · 2023-07-17T21:59:22+03:00

The ksp of CaCrO₄ is 7.13 × 10⁻⁴.

The ksp can be defined as the solubility constant of a solid sample in the aqueous solution.

The molarity of CaCrO₄ in the solution is given as:

Molarity = mass/molar mass × 1000/Volume (mL)

Molarity = 0.649 g/ 156 g/mol × 1000 / 156 mL

Molarity = 0.0267 mol/L

The solubility of CaCrO₄ is given as:

[CaCrO₄] = [Ca²⁺] [CrO₄²⁻]

ksp is given as:

ksp = Molarity of [Ca²⁺] × Molarity of [CrO₄²⁻]

ksp = s × s

ksp = s²

Substituting the values:

ksp = (0.0267)²

ksp = 7.13 × 10⁻⁴

Thus, the ksp of CaCrO₄ is 7.13 × 10⁻⁴.

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