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vlabodo [156]
3 years ago
12

Many BLANK apply trial and error to develop a product. Please Help! I have one hour to finish. 30 points

Engineering
1 answer:
Julli [10]3 years ago
8 0

Answer:

Entrepreneurs?

Explanation:

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A paper clip is made of wire 0.75 mm in diameter. If the original material from which the wire is made is a rod 25 mm in diamete
Bas_tet [7]

Answer:

True strain = 3.7704

Explanation:

Strain is the measure an object that is stretched or deformed. This occurs when a force is applied to an object. Strain deals mostly with the change in length of the object. Strain = Δ L /L = Change in Length over the original Length:

Volume Constancy :

ΔL/L0=A0/ΔA=(D0/ ΔD)=(25mm/0.75mm)^2

ΔL/L0=44.4

Engineering strain:

Engineering strain =ΔL-L0/L0=ΔL/L0-1

Engineering strain =44.4-1=43.4

True strain, ε=In(ΔL/L0)=In(43.4)=3.7704

Note that strain has no unit, so the True strain = 3.7704

8 0
4 years ago
A differential amplifier is to have a voltage gain of 100. What will be the feedback resistance required if the input resistance
yuradex [85]

Answer:

required feedback resistance ( R2 ) = 100 k Ω

Explanation:

Given data :

Voltage gain = 100

input resistance ( R1 ) = 1 k ohms

calculate feedback resistance required

voltage gain of differential amplifier

\frac{Vout}{V2 - V1 }  = \frac{R2}{R1}

= Voltage gain =  R2/R1

= 100 = R2/1

hence required feedback resistance ( R2 ) = 100 k Ω

4 0
3 years ago
Assume, X Company Limited (XCL) is one of the leading 4th generation Life Insurance
marishachu [46]

Answer:

The issues related to the privacy are:

1. Informational privacy

2. Discrimination factors

3. Biased grouping on the basis of Data mining

4. Lack of consent

5. Morally wrong

6. Illegal distribution of information risks

7. Possibility of threat to life

Let's look at some major concerns:

1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.

2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.

3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.

3 0
3 years ago
Read 2 more answers
What does the automobile rely on to function?
Montano1993 [528]

Answer:

fuel

Explanation:

all automobiles rely on fuel to function

3 0
3 years ago
A heat engine uses fuel of energy content 43.1 MJ/kg and produces 17.4 kW of useful power. The heat rejection rate (through the
solmaris [256]

Answer:

a)27.9%

b)\dot{m}=3.06 \frac{Kg}{h}

Explanation:

Given that

Fuel energy content = 73.1 MJ/kg

Useful power = 17.4 KW

Heat rejection rate = 44.8 KW

From first law of thermodynamics

Heat addition rate =Heat rejection rate + Power out put

Now by putting the values in the above formula

Heat addition rate = 44.8 + 17.4

Heat addition rate =62.2 KW

We know that efficiency is given as follows

\eta =\dfrac{power\ out\ put}{Heat\ addition\ rate}

So

\eta =\dfrac{17.4}{62.2}

\eta =0.279

So the efficiency is 27.9%.

Now to find usage rate of fuel

Lets take usage rate is \dot{m}

Fuel energy content  x  usage rate of fuel = Heat addition rate

Now by putting the values

73100\times \dfrac{\dot{m}}{3600}=62.2

\dot{m}=3.06 \frac{Kg}{h}

7 0
3 years ago
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