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vlabodo [156]
3 years ago
12

Many BLANK apply trial and error to develop a product. Please Help! I have one hour to finish. 30 points

Engineering
1 answer:
Julli [10]3 years ago
8 0

Answer:

Entrepreneurs?

Explanation:

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attached below

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An energy system can be approximated to simply show the interactions with its environment including cold air in and warm air out
Elenna [48]

Answer: The energy system related to your question is missing attached below is the energy system.

answer:

a) Work done = Net heat transfer

  Q1 - Q2 + Q + W = 0

b)  rate of work input ( W ) = 6.88 kW

Explanation:

Assuming CPair = 1.005 KJ/Kg/K

<u>Write the First law balance around the system and rate of work input to the system</u>

First law balance ( thermodynamics ) :

Work done = Net heat transfer

Q1 - Q2 + Q + W = 0 ---- ( 1 )

rate of work input into the system

W = Q2 - Q1 - Q -------- ( 2 )

where : Q2 = mCp T  = 1.65 * 1.005 * 293 = 485.86 Kw

             Q2 = mCp T = 1.65 * 1.005 * 308 = 510.74 Kw

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Insert values into equation 2 above

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5 0
2 years ago
Two previously undeformed rod-shaped specimens of copper are to be plastically deformed by reducing their cross-sectional areas.
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An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through th
sp2606 [1]

Answer:

<em> - 14.943 W/m^2K  ( negative sign indicates cooling ) </em>

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Given data:

Area of FPC = 4 m^2

temp of water = 60°C

flow rate = 0.06 l/s

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exit temperature = 49°C

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m*Cp*dT  = h*A * ( T - To )

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In ( \frac{49-8}{60-8} ) =  h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )

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hence h = - 0.2376 / 0.0159

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7 0
2 years ago
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Nuetrik [128]

Answer:

<em>hi</em><em> </em><em>sa</em><em>m</em><em>e</em><em> </em><em>here</em><em>.</em><em> </em><em>hru</em><em> </em><em>btw</em>

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3 years ago
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