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antiseptic1488 [7]
2 years ago
6

Does the work required to lift a book to a high shelf depend on how fast you raise it? does the power required to lift the book

depend on how fast you raise it? explain.
Physics
1 answer:
tatiyna2 years ago
6 0

Answer:

No

Explanation:

According to the formula W=Fx, the work done only depends on the Force applied to the book(the gravitational force of the book) and the distance to lift, which is a constant. The velocity doesn't matter.

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♡ GuYs diG cRaZy cHiCks ♡ IvE naMeD my aLtEr Ego AJ
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Explanation:

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2 years ago
If a force of 50 Newton’s was applied to an object with a mass of 500 grams, what will the objects acceleration be?
lapo4ka [179]

Answer:  100 m/s^2

F=ma

Explanation:

50N = 50 kg*m/s^2

500g = 0.5 kg

F=ma

a = F/m

a = (50 kg*m/s^2)/(0.5 kg)

a = 100 m/s^2

5 0
3 years ago
An object at rest starts accelerating.
Shalnov [3]

Answer:

<u>We are given: </u>

initial velocity (u) = 0 m/s

final velocity (v) = 10 m/s

displacement (s) = 20 m

acceleration (a) = a m/s/s

<u>Solving for 'a'</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(10)² - (0)² = 2(a)(20)

100 = 40a

a = 100 / 40

a = 2.5 m/s²

6 0
3 years ago
Which motion listed below matches the graph?
mote1985 [20]
Bro I really think it might be c
7 0
3 years ago
Read 2 more answers
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

∴ Frictional Force = 15.25 N

4 0
3 years ago
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