A gram molecule<span> of a </span>gas<span> at </span>127<span>°C </span>expands isothermally until its volume<span> is </span>doubled<span>. </span>Find<span> the </span>amount<span>of </span>work done<span> and </span>heat absorbed<span>.</span>
Answer:
see explanations below
Explanation:
At the point when the car leaves the track, the reaction on the road is zero, meaning that the centrifugal force equals the gravitation force, namely
mv^2/r = mg
Solve for v in SI units
v^2 = gr = 9.81 m/s^2 * 14.2 m = 139.302 m^2/s^2
v = sqrt(139.302) = 11.8 m/s
Answer: at 11.8 m/s (26.4 mph) car will leave the track.
Answer:
La verdad no entendi bien pero igual esta muy bien, Escoge lo que sientas en el corazón
Explanation:
Haz lo que sientas eso es lo mejor
Answer:
μ = 0.189
Explanation:
The spring potential energy will convert to work of friction
Fd = ½kx²
μmgd = ½kx²
μ = kx²/2mgd
μ = 167(0.132²) / (2(2.77)(9.81)(0.284))
μ = 0.18852424...
