I had this question before can you show me the answers choices
The problem about describes a perfectly inelastic collision. We are tasked to find the initial velocity of an object having a mass of 6 kg moving due west. It is given in the problem that after collision the cart sticks together and it stops. Thus, the final mass is the sum of the two cart and the final velocity is zero. For a perfectly inelastic collision,
m1v1-m2v2=vf(m1+m2)
By Substitution,
3(4)-6(v2)=0
6v2=12
v2=2
Therefor, the initial velocity if a 6 kg cart is 2 m/s
Answer:
The final position is 36 feet.
Explanation:
initial position, d = 330 feet
speed, v = 3 feet per minute
time, t = 30 minute
now the time is 32 minute
time interval = 2 minute
So, the distance in 2 minutes is
d' = 2 x 3 = 6 feet
So, the final position is
D = 30 + 6 = 36 feet
Yes it does. But not always
Answer:
Speed of the cars after the collision is 3.34 m/s.
Explanation:
It is given that,
Mass of one car, m₁ = 1500 kg
Velocity of this car, v₁ = + 30 m/s ( in east )
Mass of other car, m₂ = 3000 kg
Velocity of other car, v₂ = - 20 m/s (in south)
The two cars stick together after the collision. It is a case of inelastic collision. Let v is the speed of cars after collision. It can be calculated using the conservation of linear momentum as :
v = -3.34 m/s
So, the speed of the cars after the collision is 3.34 m/s. Hence, this is the required solution.
