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Artist 52 [7]
3 years ago
12

PLEASE HELP DUE TODAY!!!!!!!!

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

divide 588 by 9 then find the square root of the number it comes out too

Step-by-step explanation:

Tom [10]3 years ago
6 0

Answer:

The volume of the square base

Step-by-step explanation:

so if you take

588/9 = 65in

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Isabelle is planning a road trip to her friend's house. She looks at a map that has a scale of 1/2 in. to 25 mi. The road distan
Orlov [11]
1/2+1/2=1
2*12=24
d=24*25
d=600 miles
I believe I did it in my head so not entirely sure but I am heavily certain of my math
4 0
3 years ago
Read 2 more answers
Solve both by elimination can someone help?<br> 2x-5y=-9 , 4x+5y=12<br><br> 3x-2y=12 , 7x-5y=17
lyudmila [28]

Answer:

x=1/2, y=2;    

Step-by-step explanation:

First pair:

2x-5y =-9

4x+5y=12

Add them together:

6x=3

x = 1/2

2(1/2) - 5y =-9

1-5y = -9

1+9=5y

y=10/5=2

8 0
2 years ago
Someone please help me!!​
LiRa [457]

Answer:

no it is not

Step-by-step explanation:

4 0
3 years ago
Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs
zimovet [89]

Answer:

Your answer is B

Step-by-step explanation:

Take 300 and subtract it by 99 you'll get 201

3 times 67 is 201

Which is why your answer is B!




Hope this helps! -Queenb369


(P.S, If you could give me the brainlist if i'm right, that will be great thanks!)


6 0
4 years ago
Read 2 more answers
After being rearranged and simplified, which of the following equations could be solved using the quadratic formula?
dmitriy555 [2]
A. 2x^2 - 3x + 10 = 2x + 21
2x^2 - 3x - 2x + 10 - 21 = 0
2x^2 - 5x - 11 = 0                              (quadratic equation)

2x^2 - 6x - 7 = 2x^2
2x^2 - 2x^2 - 6x - 7 = 0
-6x - 7 = 0                                          (not a quadratic equation)

5x^2 + 2x - 4 = 2x^2
5x^2 - 2x^2 + 2x - 4 = 0
3x^2 + 2x - 4                                      (quadratic equation)

5x^3 - 3x + 10 = 2x^2
5x^3 - 2x^2 - 3x + 10 = 0                    (not a quadratic equation)

Therefore, options a and c can be solved using the quadratic formula.
3 0
3 years ago
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