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Gnesinka [82]
3 years ago
7

6. Two blocks are released from rest at the same height. Block A slides down a steeper ramp than Block B. Both ramps are frictio

nless. The blocks reach the same final height indicated by the lower dashed line. Block B weighs more than Block A.
a. Is the work done by the gravitational force on Block A (greater/less than/equal to) the work done by the gravitational force on Block B? Explain your reasoning.

b. Is the speed of Block A (greater/less than/equal to) the speed of Block B? Explain your reasoning.

c. Is the momentum of Block A (greater/less than/equal to) the momentum of Block B? Explain your reasoning.
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.

b. the speed of Block A is <u>equal to</u> the speed of Block B.

c. the momentum of Block A is <u>less than</u> the momentum of Block B.

Explanation:

a. The  work done by the gravitational force is equal to:

w = m*g*h

where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.

b. With ramps frictionless, the final speed of the blocs is:

v = √(2*g*h)

which is independent of the mass of the blocks.

c. The momentum is calculated as follows:

momentum = m*v

Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.

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slamgirl [31]

Answer:

Force,friction,inertia and momentum

Explanation:

The speed that the marble is moving at can be determined by the amount of force used when pushed or pulled and what kind of surface it's on.Momentum is also a factor because of the mass of the marbles.

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3 years ago
A particle charge of 2.7 µC is at the center of a Gaussian cube 55 cm on edge. What is the net electric flux through the surface
Alexxx [7]

Answer:

3.05×10⁵ Nm²C⁻¹

Explanation:

According to Gauss' law,

∅' = q/e₀............... Equation 1

Where ∅' = net flux through the surface, q = net charge, e₀ = electric permittivity of the space

From the question,

Given: q = 2.7 μC = 2.7×10⁻⁶ C,

Constant: e₀ = 8.85×10⁻¹² C²/N.m²

Substituting these values into equation 1

∅' = (2.7×10⁻⁶)/(8.85×10⁻¹²)

∅' = 3.05×10⁵ Nm²C⁻¹

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kifflom [539]
The odometer measures distance
5 0
3 years ago
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gtnhenbr [62]
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For rectilinear motion, the distance traveled is equal to the initial velocity times the time, plus one-half of the acceleration times the square of the time. For projectile motion, the maximum distance is equal to the square of the initial velocity multiplied with the square of the sine of the launch angle, all over twice the gravity.
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