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Gnesinka [82]
3 years ago
7

6. Two blocks are released from rest at the same height. Block A slides down a steeper ramp than Block B. Both ramps are frictio

nless. The blocks reach the same final height indicated by the lower dashed line. Block B weighs more than Block A.
a. Is the work done by the gravitational force on Block A (greater/less than/equal to) the work done by the gravitational force on Block B? Explain your reasoning.

b. Is the speed of Block A (greater/less than/equal to) the speed of Block B? Explain your reasoning.

c. Is the momentum of Block A (greater/less than/equal to) the momentum of Block B? Explain your reasoning.
Physics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.

b. the speed of Block A is <u>equal to</u> the speed of Block B.

c. the momentum of Block A is <u>less than</u> the momentum of Block B.

Explanation:

a. The  work done by the gravitational force is equal to:

w = m*g*h

where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.

b. With ramps frictionless, the final speed of the blocs is:

v = √(2*g*h)

which is independent of the mass of the blocks.

c. The momentum is calculated as follows:

momentum = m*v

Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.

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During a rainy day, as a result of colliding clouds an observer saw lighting and a heard thunder sound. The time between seeing
hodyreva [135]

Answer:

d = 1700 meters

Explanation:

During a rainy day, as a result of colliding clouds an observer saw lighting and a heard thunder sound.  The time between seeing the lighting and hearing the sound was 5 second, t = 5 seconds

Speed of sound, v = 340 m/s (say)

Let d is the distance of the colliding cloud from the observer. The distance covered by the object. It is given by :

d=v\times t

d=340\ m/s\times 5\ s  

d = 1700 meters

So, the distance of the colliding cloud from the observer is 1700 meters. Hence, this is the required solution.    

8 0
2 years ago
Please help me!! I can't figure the answer out, AND haven't gotten past this (being the block test) for a couple weeks now!!
ololo11 [35]

The density of the nugget is 19 g/cm^3 and is made of gold

Explanation:

The density of an object can be calculated as

d=\frac{m}{V}

where

d is the density

m is the mass

V is the volume of the object

We have to note that density of an object actually depends on the material the object is made of (therefore, two objects made of the same material can have different mass and different volume, but they have same density).

For the nugget in this problem, we have:

mass: m = 38 g

volume: V=2 cm^3

So, its density is

d=\frac{38}{2}=19 g/cm^3

And by looking at the table, we see that this value corresponds approximately to the density of gold, so the nugget is made of gold.

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

5 0
3 years ago
A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b
Firlakuza [10]

From the given information in the question, the correct option is Option 1: 14 cm.

A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:

PE = \frac{1}{2} k x^{2}

Where PE is the energy, k is the spring constant and x is extension.

i. Given that: PE = 10 J and x = 10 cm, then;

PE = \frac{1}{2} k x^{2}

10 = \frac{1}{2} k 10^{2}

20 = 100k

k = 0.2 J/cm

ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.

PE = \frac{1}{2} k x^{2}

20 = \frac{1}{2} (0.2) x^{2}

40 = 0.2 x^{2}

x^{2} = 200

x = \sqrt{200}

  = 14.1421

x = 14.14 cm

So that;

x is approximately 14.00 cm.

Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.

For more information, check at: brainly.com/question/1352053.

8 0
3 years ago
What group is Ne in? What is its period?
Gemiola [76]

Answer:

Neon (Ne), chemical element, inert gas of Group 18 (noble gases) of the periodic table, used in electric signs and fluorescent lamps. Colourless, odourless, tasteless, and lighter than air, neon gas occurs in minute quantities in Earth's atmosphere and trapped within the rocks of Earth's crust.

Explanation:

I am smart

8 0
2 years ago
Read 2 more answers
Margaret, a researcher, desires to conduct a field experiment to determine the effects of a shopping mall's ambience on consumer
vichka [17]

Answer:

Extraneous

Explanation:

Extraneous variables are any variables that you are not intentionally studying in your experiment or test

6 0
2 years ago
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