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lawyer [7]
4 years ago
9

What happens to light that shines on an object but is not transmitted?

Physics
1 answer:
bekas [8.4K]4 years ago
7 0
The answer is it is reflected or absorbed, so D. 
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A wire is placed between the poles of a horseshoe magnet. There is a current in the wire in the direction shown, and this causes
Liula [17]
The answer in the picture

8 0
3 years ago
A rectangular gasoline tank can hold 50.0 kg of gasoline when full. What is the depth of the tank if it is 0.500-m wide by 0.900
sweet-ann [11.9K]

Answer:

0.16 m

Explanation:

A rectangular gasoline tank can hold 50.0 kg of gasoline when full, and the density of gasoline is 6.8 × 10² kg/m³. We can find the volume occupied by the gasoline (volume of the tank).

50.0 kg × (1 m³/6.8 × 10² kg) = 0.074 m³

The volume of the rectangular tank is:

volume = width × length × depth

depth = volume / width × length

depth = 0.074 m³ / 0.500 m × 0.900 m

depth = 0.16 m

3 0
3 years ago
Find the work done in pumping gasoline that weighs 6600 newtons per cubic meter. A cylindrical gasoline tank 3 meters in diamete
almond37 [142]

Answer:

<em>work done in pumping the entire fuel is 1399761 J</em>

Explanation:

weight per volume of the gasoline = 6600 N/m^3

diameter of the tank = 3 m

length of the tank = 6 m

The height of the tractor tank above the top of the tank = 5 m

The total volume of the fuel is gotten below

we know that the tank is cylindrical.

<em>we assume that the fuel completely fills the tank.</em>

therefore, the volume of a cylinder =  

where r = radius = diameter ÷ 2 = 3/2 = 1.5 m

volume of the cylinder = 3.142 x  x 6 = 42.417 m^3

we then proceed to find the total weight of the fuel in Newton

total weight = (weight per volume) x volume

total weight = 6600 x 42.417 = 279952.2 N

therefore,

the work done to pump the fuel through to the 5 m height = (total weight of the fuel) x (height through which the fuel is pumped)

work done in pumping = 279952.2 x 5 = <em>1399761 J</em>

5 0
3 years ago
A stationary sub uses sonar to send a 1.18x10^3 hertz sound wave through ocean water. The reflected sound wave from the flat oce
vampirchik [111]

Answer:

a) v = 1524.7 m/s

b) T = 8.47*10^-4 s

   λ = 1.29 m

Explanation:

a) First, in order to calculate the speed of the sound wave, you take into account that the velocity is constant, then, you use the following formula:

v=\frac{d}{t}

d: distance traveled by the sound wave, which is twice the distance to the ocean bottom = 2*324 m = 648 m

t: time that sound wave takes to return to the sub = 0.425

v=\frac{648m}{0.425s}=1524.7\frac{m}{s}

hence, the speed of the sound wave is 1524.7 m/s

b) Next, with the value of the velocity of the wave you can calculate the wavelength of the wave, by using the following formula:

v=\lambda f\\\\\lambda=\frac{v}{f}

f: frequency = 1.18*10^3 Hz

\lambda=\frac{1524.7m/s}{1.18*10^3s^{-1}}=1.29m

And the period is:

T=\frac{1}{f}=\frac{1}{1.18*10^3s^{-1}}=8.47*10^{-4}s

hence, the wavelength and period of the sound wave is, respectively, 1.29m and 8.47*10^-4 s

5 0
3 years ago
Select all of the answers that can serve as a meaning for sexuality. (more than one answer may be selected)
Aneli [31]
Gender and self esteem is the answer
5 0
3 years ago
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