Explanation:
The given data is as follows.
Temperature of metal =
= (296 + 273) K
= 569 K
Density of the metal = 8.85
=
(as
)
Atomic mass = 51.40 g/mol
Vacancies = 
Formula to calculate the number of atomic sites is as follows.
n = 
= 
= 
Now, we will calculate the energy as follows.
E = 
where, K = 
E = 
= 
Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is
.
Answer:
incomplete data
Explanation:
no mass is given.
no vertical height is given
Answer:
x(t)=0.337sin((5.929t)
Explanation:
A frictionless spring with a 3-kg mass can be held stretched 1.6 meters beyond its natural length by a force of 90 newtons. If the spring begins at its equilibrium position, but a push gives it an initial velocity of 2 m/sec, find the position of the mass after t seconds.
Solution. Let x(t) denote the position of the mass at time t. Then x satisfies the differential equation
Definition of parameters
m=mass 3kg
k=force constant
e=extension ,m
ω =angular frequency
k=90/1.6=56.25N/m
ω^2=k/m= 56.25/1.6
ω^2=35.15625
ω=5.929
General solution will be
differentiating x(t)
dx(t)=-5.929c1sin(5.929t)+5.929c2cos(5.929t)
when x(0)=0, gives c1=0
dx(t0)=2m/s gives c2=0.337
Therefore, the position of the mass after t seconds is
x(t)=0.337sin((5.929t)
The correct answer is the energy of the sun
Answer:
0° C = 273.15 K
0 K = - 273.15° C
Explanation:
<em>Hello there!</em>
The Kelvin temperature scale refers to the absolute temperature scale. The division in the Kelvin scale is equal to a degree on the Celsius scale only it's difference is zero
The Celsius scale of zero (0°C) is the freezing point.
0 K is Absolute Zero.
•°• 0 K = - 273.15° C
0° C = 273.15 K
Furthermore, this is what I would like you to know about this scales;
<em>The </em><em>Kelvin </em><em>scale </em><em>is </em><em>used </em><em>for</em><em> </em><em>very </em><em>low </em><em>or </em><em>very </em><em>high </em><em>temperatures</em><em> </em><em>where </em><em>water </em><em>is </em><em>not </em><em>involved</em><em>.</em>
<em>Note:</em><em> </em>
<em>The </em><em>boiling</em><em> point</em><em> of</em><em> water</em><em> is</em><em> </em><em>1</em><em>0</em><em>0</em><em>°</em><em>C</em><em>.</em>
I hope this helps you to understand more on this scales. Have a nice studies.