Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:
where n = number density
Substituting for P, k and T in equation (2) gives:
Next, substituting for n and σ in equation (1) gives:
if you know what kind of chemical a reactant is, it can help you to quickly distinguish the chemical reaction.
Ex:
HCl + KOH <---> KCl + H2O
We can look at the reactants and identify that this reaction is an acid-base reaction because HCl is an acid (it gave a proton) and KOH is a base (it accepted the proton)
Hmmmm not sure I’ll tell u when I know
Answer:
2 M Al³⁺(aq) and 6 M NO₃⁻(aq)
Explanation:
Al(NO₃)₃ is a strong electrolyte that ionizes according to the following equation.
Al(NO₃)₃(aq) → Al³⁺(aq) + 3 NO₃⁻(aq)
The solution 2.0 M contains 2.0 moles of Al(NO₃)₃ per liter of solution.
The molar ratio of Al(NO₃)₃ to Al³⁺ is 1:1. The concentration of Al³⁺ is:
2.0 mol Al(NO₃)₃/L × (1 mol Al³⁺/1 mol Al(NO₃)₃) = 2.0 mol Al³⁺/L = 2.0 M Al³⁺
The molar ratio of Al(NO₃)₃ to NO₃⁻ is 1:3. The concentration of NO₃⁻ is:
2.0 mol Al(NO₃)₃/L × (3 mol NO₃⁻/1 mol Al(NO₃)₃) = 6.0 mol NO₃⁻/L = 6.0 M NO₃⁻