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adoni [48]
3 years ago
9

Select the correct location on the image.

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

Violet (Shortest Wave Length)

Explanation:

Violet waves have the highest frequencies. The highest frequencies have the shortest wave length.

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You and a friend are playing with a bowling ball to demonstrate some ideas of Rotational Physics. First, though, you want to cal
RideAnS [48]

Answer:

K_{total} = 19.4 J

Explanation:

The total kinetic energy that is formed by the linear part and the rotational part is requested

         K_{total} = K_{traslation}  + K_{rotation}

let's look for each energy

linear

        K_{traslation} = ½ m v²

rotation

        K_{rotation} = ½ I w²

the moment of inertia of a solid sphere is

       I = 2/5 m r²

we substitute

       K_{total} = ½ mv² + ½ I w²

           

angular and linear velocity are related

           v = w r

we substitute

           K_{total} = ½ m w² r² + ½ (2/5 m r²) w²

           K_{total} = m w² r² (½ + 1/5)

           K_{total} = \frac{7}{10} m w² r²

let's calculate

           K_{total} = \frac{7}{10}   6.40 16.0² 0.130²

           K_{total} = 19.4 J

6 0
3 years ago
Charge is uniformly distributed throughout a spherical insulating volume of radius R=4.00 cm . The charge per unit volume is −6.
aleksley [76]

Answer

-8.67× 10^6 N/C

Explanation:

The Electric Field is defined as force per unit charge.

E = Q/ 4π£r2

Qv= −6.5 μCm3

Qv = Q/ V= Q/ 4/3 πr3

Hence Q = 4/3 πr3 × Qv

Hence E = 4/3 πr3 × Qv / 4π£r2= Qvr/3£

−6.5 μ × 4/ 3×8.854 ×10^-12

-6.5 × 4 × 10^6/3 = -8.67× 10^6 N/C

Note: £ = 8.854×10^-12m/F

is the permittivity of free space

Qv is the charge per unit volume

V is volume and volume

8 0
3 years ago
Car B is being pushed by a force of 22000 N. If it has a mass of 1375 kg.,
Burka [1]

Answer:

a = 16 m/s²

General Formulas and Concepts:

<u>Dynamics</u>

Newton's Law of Motions

  • Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  • Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  • Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

<u>Step 2: Find Acceleration</u>

  1. Substitute in variables [Newton's 2nd Law of Motion]:                                 22000 N = (1375 kg)a
  2. Isolate <em>a</em>:                                                                                                            16 m/s² = a
  3. Rewrite:                                                                                                             a = 16 m/s²
5 0
3 years ago
Waves are observed passing under a dock. Wave crests are 8.0 meters apart. The time for a complete wave to pass by is 4.0 second
Harlamova29_29 [7]
The distance between a trough and a crest is double the amplitude.

The distance between trough and crest is (9m - 6m) = 3m.

So the amplitude of those water waves is (3/2) = 1.5 meters.

For this question, we really don't need to know how far apart the crests are, or how often they pass.  There may be more parts to the question, for which that information is needed.

For example: 

-- What's the wavelength of the waves ?  8 meters.

-- What's the period of the waves ?  4 seconds.

-- What's the frequency of the waves ?  1 / (4 seconds) = 0.25 Hz.

-- What's the speed of the waves ? (8 m) x (0.25 Hz) = 2 m/s
3 0
3 years ago
A 2.1-kg brick is placed gently upon a 2.9-kg cart originally moving with a speed of 26 cm/s. determine the post-collision speed
vagabundo [1.1K]
By conservation of linear amount of movement, we have to
 p1 = p2
 Where, p = m * v.
 So, using the definition for this case, we have:
 (2.9 kg)•(26 cm/s) = (2.1 kg + 2.9 kg)•v 
 75.4 kg•cm/s = (5.0 kg)•v 
 v = 15.1 cm/s
6 0
4 years ago
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