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2 years ago

Which elements occupy the same group in the periodic table

Chemistry

1 answer:

Aleks [24]2 years ago

3 0

Answer:

Elements that occupy the same column on the periodic table

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How many moles of ions are in 285 ml of 0.0150 m mgcl2?

Solnce55 [7]

MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol

7 0

4 years ago

Read 2 more answers

What is the relationship between atoms, elements and compounds?

KatRina [158]

Compound is formed when two or more chemical elements are chemically bonded together. elements are made of atoms

4 0

3 years ago

Suppose the decomposition of dinitrogen monoxide proceeds by the following mechanism:

photoshop1234 [79]

Answer:

Part A: 2N₂O(g) ⇄ 2N₂(g) + O₂(g)

Part B: -r = K*[N₂O]²

Part C: K= k1*k2

Explanation:

Part A

To do the balance chemical question for the overall chemical reaction, we must sum the reaction of the steps, eliminating the intermediaries, which are the compounds that have the same amount both at reactants and products (bolded).

N₂O(g) ⇄ N₂(g) + O(g)

N₂O(g) + O(g) ⇄ N₂(g) + O₂(g)

---------------------------------------------

2N₂O(g) + O(g) ⇄ 2N₂(g) + O(g) + O₂(g)

2N₂O(g) ⇄ 2N₂(g) + O₂(g)

Part B

The velocity of the reaction (r) can be calculated based on the reactants or based on the products. Let's do it based on the disappearing of the reactant. Because it is disappearing, the variation at its concentration must be negative, so the rate will be negative.

Let's suppose its an elementary reaction, so, the concentration of the reactant must be elevated by its coefficient. And let's call the overall rate constant as K:

-r = K*[N₂O]²

Part C

Because the steps were summed, and the reactions were not multiplied by a constant or inverted, the constant K is just the multiplication of the constants of the steps:

K= k1*k2

8 0

3 years ago

How many significant figures are in 6.00 in

Free_Kalibri [48]

Answer:

Explanation:

5 0

4 years ago

Read 2 more answers

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

14.4 g of CaO must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

Needed = 11.31 g

Available CO2 = 13.8 g (given)

So CO2 is in excess , hence CaO is the limiting reagent and product will produce from 14.4 g of CaO

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago