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2 years ago

1 7.1.2 Quiz: Electrostatics

Physics

1 answer:

Veseljchak [2.6K]2 years ago

5 0

Answer:

charge and distance

Explanation:

The electric force between the two particles are calculated using the formular:

F = kQ₁Q₂ / d²

where:

F = force.

k= Coulomb's law constant.

Q1 and Q2 are the charges.

d= distance.

the equation above is called Coulomb's law.

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.

so the correct option is charge and distance.

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A standard inverting op-amp circuit has an R1 of 10 kΩ and an Rf of 220 kΩ. If the offset current is 100 nA the output offset vo

kiruha [24]

Answer:

The value is $V_{os} = 0.001 \ V$

Explanation:

From the question we are told that

The circuit resistance is $R_1 = 10 \ k \Omega$

The feedback resistance is $R_f = 220 \ k \Omega$

The offset current is $I_{os } = 100 \ nA = 100 * 1)^{-9} \ A$

Generally the offset voltage is mathematically reparented as

$V_{os} = R_f * I_{os}$

=> $V_{os} = 10 *10^{3}* 100 *10^{-9}$

=> $V_{os} = 0.001 \ V$

6 0

3 years ago

If the room radius is 4.5 m, and the rotation frequency is 0.8 revolutions per second when the floor drops out, what is the mini

kondaur [170]

The force of static friction F equals the coefficient of friction u times the normal force N the object exerts on the surface: F = uN. N is the centripetal force of the wall on the people; N = ma_N, where m is the mass of the people and a_N is the centripetal acceleration. The people will not slip down if F is greater than the force of gravitation: F = uma_N > mg, or u > g/a_N. a_N is the velocity v of the people squared divided by the radius of the room r: a_N = v^2/r. The circumference of the room is 2 pi r = 28.3 m. So v = 28.3 * 0.8 m/sec = 22.6 m/sec. So a_N = 114 m/sec^2. g = 9.81 m/sec^2, so u must be at least 9.81/114 = 0.086.

3 0

3 years ago

Find the frequency of a wave produced by a generator that emits 100 pulses in 2.0 s.

kobusy [5.1K]

The frequency of the wave is 50 Hz

Explanation:

The frequency of the wave is defined as the number of cycles per second of the wave:

$f=\frac{N}{t}$

where

N is the number of cycles completed in a time t.

Frequency is measured in Hertz (Hz).

In this problems, the wave has

N = 100 pulses

t = 2.0 s

Therefore, its frequency is

$f=\frac{100}{2.0}=50 Hz$

Learn more about waves and frequency here:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

7 0

3 years ago

An object has a kinetic energy of 175 J and a momentum of magnitude 25.0 kg m/s. Find the

DedPeter [7]

Answer:14 m/s

Explanation:

Kinetic energy(ke)=175J

Momentum(M)=25kgm/s

Speed=v

Mass=m

Ke=(m x v x v)/2

175=(mv^2)/2

Cross multiply

175 x 2=mv^2

350=mv^2

Momentum=mass x velocity

25=mv

m=25/v

Substitute m=25/v in 350=mv^2

350=25/v x v^2

350=25v^2/v

v^2/v=v

350=25v

v=350/25

v=14 m/s

5 0

4 years ago

If an automobile engine delivers a power of 50.0 hp, how much time will it take for the engine to do 6.40 x 10^4 j of work? (1 h

aleksandrvk [35]

Given data

Power (P) = 50 hp,

= 50 × 746, we know that 1 hp = 746 W.

= 37300 Watts (Watt = J/s)

Work = 6.40 ×10⁴ J

Power is defined as rate of doing work and the unit of power is Watt.

Mathematically,

Power = (Work / time) Watts

= 6.40 ×10⁴ / time

37300 W = 6.40 ×10⁴ J /time (Where time in seconds)

=> time = Work/Power

= 6.40 ×10⁴/37300

= 1.74 seconds

Therefore , the engine need 1.74 seconds to do 6.40 6.40 ×10⁴ J of work 

 

7 0

4 years ago