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2 years ago

1 7.1.2 Quiz: Electrostatics

Physics

1 answer:

Veseljchak [2.6K]2 years ago

5 0

Answer:

charge and distance

Explanation:

The electric force between the two particles are calculated using the formular:

F = kQ₁Q₂ / d²

where:

F = force.

k= Coulomb's law constant.

Q1 and Q2 are the charges.

d= distance.

the equation above is called Coulomb's law.

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.

so the correct option is charge and distance.

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3 years ago

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Answer:

(a) 3.807 s

(b) 145.581 m

Explanation:

Let Δt = t2 - t1 be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. We know that before the acceleration, both vehicles are travelling at a constant speed. So they would maintain a distance of 58 m prior to the acceleration.

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The distance traveled by the motorcycle after Δt (seconds) at $m_m = 23 m/s$ speed and acceleration of a = 8 m/s2 is

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$s_m = s_c + 58$

$23 \Delta t + 4 \Delta t^2 = 23\Delta t + 58$

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3 years ago

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3 years ago

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3 years ago

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A parallel-plate capacitor has a plate area of 0.2 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magni

barxatty [35]

Answer:

The potential difference across the plates is 226 V.

Explanation:

Given;

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separation, d = 0.1 mm = 0.1 x 10⁻³ m

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Charge on the capacitor is given by;

Q = CV

Where;

C is the capacitance of the capacitor, given as;

C = ε₀A / d

Then, the potential difference across the plates is given by;

$V = \frac{Q}{C} = \frac{Qd}{\epsilon_o A} = \frac{(4*10^{-6})(0.1*10^{-3})}{(8.85*10^{-12})(0.2)}\\\\V = 226 \ V$

Therefore, the potential difference across the plates is 226 V.

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3 years ago