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2 years ago

Describe the energy transformation that occurs when a television is used

Engineering

1 answer:

Morgarella [4.7K]2 years ago

6 0

A television transforms electric energy into sound energy and radiant energy.

<h3>What is energy transformation?</h3>

Energy transformations are processes that convert energy from one type into another. Any type of energy use must involve some sort of energy transformation.

Some examples of energy transformations are, A television converts electric energy into sound and light energy. Lightbulbs convert electric energy into light energy. A hair dryer converts electrical energy into thermal and sound energy.

Learn more about Energy transformations here,

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That due to the specific tasks that needs to be accomplished by each program to make an all encompassing program would be inefficient and full of bugs

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2 years ago

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How large a force is required to accelerate a 1300 kg car from rest to a speed of 20 m/s in a distance of 80 m?

topjm [15]

F=m*a

F=80*20

F =1600 ans"

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Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at 1400 K and rejects th

Aleksandr-060686 [28]

Answer:

The temperature T= 648.07k

Explanation:

T1=input temperature of the first heat engine =1400k

T=output temperature of the first heat engine and input temperature of the second heat engine= unknown

T3=output temperature of the second heat engine=300k

but carnot efficiency of heat engine = $1 - \frac{Tl}{Th} \\$

where Th =temperature at which the heat enters the engine

Tl is the temperature of the environment

since both engines have the same thermal capacities <em> $n_{th}$ </em> therefore $n_{th} =n_{th1} =n_{th2}\\n_{th }=1-\frac{T1}{T}=1-\frac{T}{T3}\\ \\= 1-\frac{1400}{T}=1-\frac{T}{300}\\$

We have now that

$\frac{-1400}{T}+\frac{T}{300}=0\\$

multiplying through by T

$-1400 + \frac{T^{2} }{300}=0\\$

multiplying through by 300

- $420000+ T^{2} =0\\T^2 =420000\\\sqrt{T2}=\sqrt{420000} \\T=648.07k$

The temperature T= 648.07k

5 0

3 years ago

To compute the energy used by a motor, multiply the power that it draws by the time of operation. Con- sider a motor that draws

ehidna [41]

Answer:

E=52000Hp.h

E=38724920Wh

E=1.028x10^11 ftlb

Explanation:

To solve this problem you must multiply the engine power by the time factor expressed in h / year, to find this value you must perform the conventional unit conversion procedure.

Finally, when you have the result Hp h / year you convert it to Ftlb and Wh

$E=(12.5hp)(\frac{16h}{day} )(\frac{5 days}{week} )(\frac{52week}{year} )\\$