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Deffense [45]
3 years ago
8

What motivated arrhenius to calculate how changes in carbon dioxide might affect the climate?

Chemistry
1 answer:
DerKrebs [107]3 years ago
4 0
Arrhenius was seeking to understand the causes of ice ages. 
He was the first to use basic principles of  physical chemistry to calculate estimates of the extent to which increases in atmosphere carbon dioxide increases Earth's surface temperature through the Arrhenius effect. Arrhenius's paper was the first to quantify the contribution of carbon dioxide to the greenhouse effect and to speculate whether variations in the atmospheric concentration of carbon dioxide have contributed to long-term variations in climate.
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What is the best way to determine if an aqueous solution of sodium nitrate is unsaturated
Marina86 [1]
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It may be noted that, solubility of system is depends on temperature. 

Now, if solution is unsaturated then it will dissolve more solute, when added in it. Thus,  <span>sodium nitrate when added to solution get dissolves, it suggest that solution is unsaturated. </span>
6 0
3 years ago
How many periods does the modern periodic table have?
dusya [7]
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8 0
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suppose the mass spectrum of a hypothetical monatomic element X contains a signal at mass number 13 and another of identical hei
Illusion [34]
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6 0
3 years ago
What is the half life of the element in the picture<br><br> HELP BRAINLIEST
stira [4]

Answer:

6 days

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 100 mg

Amount remaining (N) = 6. 25 mg

Time (t) = 24 days

Half life (t½) =?

Next, we shall determine the decay constant. This can be obtained as follow:

Original amount (N₀) = 100 mg

Amount remaining (N) = 6. 25 mg

Time (t) = 24 days

Decay constant (K) =?

Log (N₀/N) = kt / 2.303

Log (100/6.25) = k × 24 / 2.303

Log 16 = k × 24 / 2.303

1.2041 = k × 24 / 2.303

Cross multiply

k × 24 = 1.2041 × 2.303

Divide both side by 24

K = (1.2041 × 2.303) / 24

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Finally, we shall determine the half-life of the isotope as follow:

Decay constant (K) = 0.1155 /day

Half life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 0.1155

t½ = 6 days

Therefore, the half-life of the isotope is 6 days

5 0
2 years ago
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abruzzese [7]

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3 0
3 years ago
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