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andrew11 [14]
2 years ago
5

If a 3 kg block rests on a rough horizontal table and experienced a 2 N force of static friction then what is the coefficient of

static friction between the block and the table
Physics
1 answer:
Jobisdone [24]2 years ago
8 0

The coefficient of static friction of the block is 0.068.

<h3 />

<h3>What is static friction?</h3>

This is the force between two bodies in contact and tends to oppose their motion. It is also the force that keeps two bodies at rest

To calculate the coefficient of static friction, we use the formula below.

Formula:

  • F = mgμ............. Equation 1

Where:

  • F = Horizontal force
  • m = mass of the block
  • g = acceleration due to gravity
  • μ = coefficient of static friction.

Make μ the subject of the equation

  • μ = F/mg.............. Equation 2

From the question,

Given:

  • m = 3 kg
  • g = 9.8 m/s²
  • F = 2 N

Substitute these values into equation 2

  • μ = 2/(3×9.8)
  • μ = 2/29.4
  • μ = 0.068.

Hence, The coefficient of static friction of the block is 0.068.

Learn more about static friction here: brainly.com/question/13680415

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A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5
Paul [167]

Answer:

Energy lost due to friction is 22 J      

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball KE=\frac{1}{2}mv^2

KE=\frac{1}{2}\times 4\times 6^2=72J

Now due to friction velocity decreases to 5 m/sec

Kinetic energy become

KE=\frac{1}{2}\times 4\times 5^2=50J

Therefore energy lost due to friction = 72 -50 = 22 J

8 0
3 years ago
A sample of copper has a volume of 23.4 cm3 if the density of copper is 8.9 gcm3 what is the coppers mass?
murzikaleks [220]
The answer is:  " 208 g " .
_____________________________________________
Explanation:
__________________________________________
The formula/ equation for density is:
__________________________________________
D = m / V  ;  That is,  "mass divided by volume" ;
 
Density is expressed as:
__________________________________________    
                   "mass per unit volume";  in which the "mass" is expressed in units of "g" ("grams") ;  and the "unit volume" is expressed in units of:
    "cm³ " or "mL"; 
_____________________________________________
           {Note the exact equivalent:  1 cm³ = 1 mL }.
____________________________________________
         →  The formula is:  " D = m / V "  ; 
___________________________________________
   in which:

     "D" refers to the "density" (see above), which is: "8.9 g/cm³ " (given); 

     "m" refers to the "mass" , in units of "g" (grams), which is unknown; and we want to find this value;
                 
     "V" refers to the "volume", in units of "cm³ " ;
               which is:  "23.4 cm³ " (given);
_________________________________________________
                 We want to find the mass, "m" ; so we take the original equation/formula for the density:
_________________________________________________ 
              D  =  m / V ; 
_________________________________________________________
             And we rearrange; to isolate "m" (mass) on ONE side of the    equation; and then we plug in our known/given values;
 to solve for "m" (mass);  in units of "g" (grams) ;
___________________________________________________
    Multiply each side of the equation by "V" ; 
____________________________________________________
             V * { D  =  m / V } ;  to get:
____________________________________________________
      V * D = m ;   ↔   m = V * D ;
___________________________________________________
           Now, we plug in the given values for "V" (volume) and "D" (density) ;     to solve for the mass, "m" ;
______________________________________________________
           m  =  V * D ;
 
           m  =  (23.4 cm³) * (8.9 g / 1 cm³)  = (23.4 * 8.9) g = 208.26 g ;
  
 →  Round to "208 g" (3 significant figures);  
____________________________________
The answer is:  " 208 g " .
_____________________________________________________
7 0
3 years ago
According to newtons third law, the two forces in a force pair act
aliina [53]
B- Same force


It’s b because force always acts in equal but opposite pairs.
6 0
3 years ago
In a Hall-effect experiment, a current of 3A sent lengthwise through a conductor of 1 cm wide, 4 cm long,
Marina CMI [18]

Answer:drift velocity is 1.7*10^-4m/s and number of charge is 2.7*10^-24

Explanation:

4 0
3 years ago
Who published the first journal of experimental psychology?
raketka [301]

Answer:

Who published the first journal of experimental psychology?

American Psychological Association published the first journal of experimental psychology.

xXxAnimexXx

Happy labor day!

6 0
3 years ago
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