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marshall27 [118]
2 years ago
12

For the following H30 concentration list the pH and the OH concentration in

Chemistry
2 answers:
Alenkinab [10]2 years ago
6 0

Answer:

[H3O+] = 1.4*10^-5 M

pH = 4.85

[OH-] = 7.08*10^-10

Explanation:

As pH is a measure of hydronium H3O concentration, simply substitute [H3O+] into the following equation:
pH = -log[H+]
pH = -log(1.4*10^-5)
pH = 4.853871...
Round to 2-3 sig figs due to only being given data with 2 significant figures
pH = 4.85

One method to get to [OH-] is to turn pH into pOH and then use inverse functions to get [OH-]
pH + pOH = 14
4.85 + pOH = 14
pOH = 9.15

Then to get [OH-] from pOH:
pOH = -log[OH-]
9.15 = -log[OH-]
-9.15 = log[OH-]
10^(-9.15) = [OH-]
7.07945784 * 10^-10 = [OH]
Round based on given significant figures again:
7.08*10^-10 = [OH-]

(Feel free to add any questions & I'll be sure to reply if clarification is needed)

Sati [7]2 years ago
3 0

[H₃O]=1.4 x 10⁻⁵

pH = 5 - log 1.4

pOH = 9 + log 1.4

[OH⁻] = 1 x 10⁻¹⁴ : 1.4 x 10⁻⁵ = 7.14 x 10⁻¹⁰

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Consider these ground-state ionization energies of oneelectron species:
SVETLANKA909090 [29]

Answer:

Explanation:

general expression for the ionization energy of any one-electron species.

=  z² x ground level energy / n²

z is atomic no , n is energy level .

ground level energy of

 H = 1.31 x 10³ kJ/mol

He⁺ = 2² x  1.31 x 10³ kJ/mol  =  5.24 x 10³ kJ/mol

Li²⁺ = 3² x  1.31 x 10³ kJ/mol   = 1.18 x 10⁴ kJ/mol

b ) the ionization energy of B⁴⁺.

= 5² x 1.31 x 10³ kJ/mol  = 32.75 x 10³ kJ/mol  

c )  minimum energy required to remove the electron from the n = 3 level of He⁺ per mole

= 5.24 x 10³ / 9  kJ/mol

= 5.82 x 10² kJ/mol

= 5.82 x 10² x 10³ / 6.02 x 10²³ J

.9667 X 10⁻¹⁸ J

= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV

= 6.042 eV

= 1237.5 / 6.042

= 204.82 nm

=

d )

3 0
3 years ago
Predict the shape and hybridization of platinum tetrachloride (PfCl4)​
guapka [62]

Answer:

Shape- square planar , hybridisation-sp3

Explanation:

Shape:

  1. VSPER theorey is used to determine both electron geometry and molecular geometry of a molecule.(PtCl4)2 molecular geometry is square planar
  2. Hybridisation:It undergoes sp3 hybridisation.since there are 2 unpaired electrons in this case, it is paramagnetic in nature
3 0
3 years ago
Please help, due tomorrow! ツ
oksano4ka [1.4K]

There are two kinds of mixtures

a) homogeneous : the boundary of the two components is not physically distinct

b) heterogeneous:the boundary of the two components is  physically distinct

the following separation techniques are common for mixtures

1) filtration: if the two components are forming heterogeneous mixture we can separate them by filtration.

2) boiling: if boiling point of one of the components is less than other

3) magnetic separation: if one of the component is magnetic

4)sieve method: for solid components with difference in size of particles

5) hand picking

Thus the correct match will be as shown in the figure


3 0
3 years ago
What is the IUPAC name of the following compounds i. CO₂ ii. NO₂ iii. HNO3 iv. H₂SO4 v. K-Cr₂O vi. [Fe(CN)
Zielflug [23.3K]

Explanation:

I) carbon dioxide

ii) nitrogen dioxide

iii) nitric acid

iv) sulphric acid

v) Potassium dichromate

vi) hexacyanoferrate (III) ion( not sure)

8 0
2 years ago
If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4
abruzzese [7]

<u>Answer:</u> The limiting reagent in the given chemical reaction is carbon metal.

<u>Explanation:</u>

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium sulfate:</u>

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol

  • <u>For carbon:</u>

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol

For the given chemical reaction:

Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = \frac{1}{4}\times 0.31=0.0775mol of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

4 0
3 years ago
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