The sun’s energy is most useful to humans after it is converted to _____.
1 answer:
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Answer:
a) p₂ = 1.88 kg*m/s
θ = 273.4 º
b) Kf = 37% of Ko
Explanation:
a)
- Assuming no external forces acting during the collision, total momentum must be conserved.
- Since momentum is a vector, their components (projected along two axes perpendicular each other, x- and y- in this case) must be conserved too.
- The initial momenta of both particles are directed one along the x-axis, and the other one along the y-axis.
- So for the particle moving along the positive x-axis, we can write the following equations for its initial momentum:
- We can do the same for the particle moving along the positive y-axis:
- Now, we know the value of magnitude of the final momentum p1, and the angle that makes with the positive x-axis.
- Applying the definition of cosine and sine of an angle, we can find the x- and y- components of the final momentum of the first particle, as follows:
- Now, the total initial momentum, along these directions, must be equal to the total final momentum.
- We can write the equation for the x- axis as follows:
- We know from (3) that p₀₂ₓ = 0, and we have the values of p₀1ₓ from (1) and pf₁ₓ from (5) so we can solve (7) for pf₂ₓ, as follows:
- Now, we can repeat exactly the same process for the y- axis, as follows:
- We know from (2) that p₀1y = 0, and we have the values of p₀₂y from (4) and pf₁y from (6) so we can solve (9) for pf₂y, as follows:
- Since we have the x- and y- components of the final momentum of the second particle, we can find its magnitude applying the Pythagorean Theorem, as follows:
- We can find the angle that this vector makes with the positive x- axis, applying the definition of tangent of an angle, as follows:
- The angle that we are looking for is just the arc tg of (12) which measured in a counter-clockwise direction from the positive x- axis, is just 273.4º.
b)
- Assuming that both masses are equal each other, we find that the momenta are proportional to the speeds, so we find that the relationship from the final kinetic energy and the initial one can be expressed as follows:
- So, the final kinetic energy has lost a 37% of the initial one.
Answer: The length of the shadow on the wall is decreasing by 0.6m/s
Explanation:
the specified moment in the problem, the man is standing at point D with his head at point E.
At that moment, his shadow on the wall is y=BC.
The two right triangles ΔABC and ΔADE are similar triangles. As such, their corresponding sides have equal ratios:
ADAB=DEBC
8/12=2/y,∴y=3 meters
If we consider the distance of the man from the building as x then the distance from the spotlight to the man is 12−x.
(12−x) /12=2/y
1− (1 /12x )=2 × 1/y
Let's take derivatives of both sides:
−1 / 12dx = −2 × 1 / y^2 dy
Let's divide both sides by dt:
−1/12⋅dx/dt=−2/y^2⋅dy/dt
At the specified moment:
dxdt=1.6 m/s
y=3
Let's plug them in:
−1/121.6) = - 2/9 × dy/dt
dy/dt = 1.6/12 ÷ 2/9
dy/dt = 1.6/12 × 9/2
dy/dt = 14.4/24 = 0.6m/s
Well...
The force would double because the product of mass and acceleration is doubled.
The force would double because the product of mass and acceleration is doubled.