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kaheart [24]
2 years ago
5

How many moles of oxygen are needed to react completely with 17.2 moles of aluminum

Chemistry
1 answer:
Butoxors [25]2 years ago
4 0

Answer:As you have asked, I will not do your homework for you but will outline the reasoning…

Find out the atomic weight of all the species involved in the problem. Three decimals is more than sufficient.

Look at the periodic table of the elements and other resources (notes!) as necessary to determine the expected valence of the species

Once you know how many of these go with those, you are cruising…

You already know that  4Al+3O2→2Al2O3

So, you are in a great position to determine the number of moles of  O2 , as you know you have 14.8 mol of Al and the ratio of combination is always 4 molecules.

Explanation:

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Answer:

0.44 L.

Explanation:

Density of nickel(II) chloride = 29.8 g/dL.

Mass of nickel(II) chloride = 131 g

Volume of nickel(II) chloride =?

Next, we shall convert 29.8 g/dL to g/L. This can be obtained as follow:

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1 g/dL = 10 g/L

Therefore,

29.8 g/dL = 29.8 x 10 = 298 g/L

Therefore, 29.8 g/dL is equivalent to 298 g/L.

Finally, we shall determine the volume of nickel(II) chloride as follow:

Density of nickel(II) chloride = 298 g/L

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Volume of nickel(II) chloride =?

Density = mass /volume

298 = 131/Volume

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298 x Volume = 131

Divide both side by 298

Volume = 131/298

Volume = 0.44 L

Therefore, the volume of of nickel(II) chloride is 0.44 L

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