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3 years ago

All electric circuits have devices that are run by _____ energy.

Physics

1 answer:

KATRIN_1 [288]3 years ago

8 0

Answer: electrical energy

Explanation:

Electrical energy

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Assume that two of the electrons at the negative terminal have attached themselves to a nearby neutral atom. There is now a nega

devlian [24]

Answer: its negative

Explanation: becase it is

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3 years ago

A boat radioed a distress call to a Coast Guard station. At the time of the call, a vector A from the station to the boat had a

VashaNatasha [74]

Answer:

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

$r_1 = 45 sin15 \hat i + 45 cos15 \hat j$

$r_1 = 11.64 \hat i + 43.46\hat j$

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

$r_2 = 30 cos15\hat i + 30 sin15 \hat j$

$r_2 = 28.98\hat i + 7.76 \hat j$

now the displacement of the boat is given as

$d = r_2 - r_1$

$d = (28.98\hat i + 7.76 \hat j) - (11.64 \hat i + 43.46\hat j)$

$d = 17.34 \hat i - 35.7 \hat j$

so the magnitude is given as

$d = \sqrt{17.34^2 + 35.7^2}$

$d = 39.7 km$

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3 years ago

What is conductivity?

kirill [66]

Answer:

Conductivity is the measure of the ease at which an electric charge or heat can pass through a material. A conductor is a material that gives very little resistance to the flow of an electric current or thermal energy.

Explanation:

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3 years ago

Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge of Object 2 is tripled, then the new

Leya [2.2K]

Answer:

The force will be 54.0 units

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's Law:

$F=\frac{kq_1 q_2}{r^2}$

where

k is Coulomb's constant

q1, q2 are the magnitude of the two charges

r is the separation between the two charges

From the equation, we see that the magnitude of the force is directly proportional to the charge of object 2:

$F\propto q_2$

In this problem, the initial force between the two objects is

F = 18.0 N

And so, when the charge on object 2 is tripled,

$q_2'=3q_2$

The new electrostatic force will be

$F'\propto q_2' = (3q_2) = 3F$

So, the force will also triple: since the original force was 18.0 units, the new force will be

$F'=3F=3(18.0)=54.0$

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3 years ago

Make the following conversion.

blsea [12.9K]

Answer: 56320

Explanation:

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3 years ago

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