1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sergeinik [125]
2 years ago
6

A Certain gas weighs 60g. IF the relative molecular mass of the gas is 12 what is the volume of the gas?​

Chemistry
1 answer:
GaryK [48]2 years ago
8 0
Hm I’m not sure could you support more detail
You might be interested in
At elevated temperatures, sodium chlorate decomposes to produce sodium chloride and oxygen gas. A 0.8765-g sample of impure sodi
barxatty [35]

Answer:

z = 18,46%

Explanation:

First we need to discover the mole number of the O2 produced so we use PV=nRT

734 torr * 57.2*10^-3 L = n 62.3637 * 295.15 K

n = \frac{734 * 57.2*10^-3}{62.3637 * 295.15}

n = \frac{41,98}{18.406}

n = 2,28 * 10^-3 mole

The reaction to the decomposition is:

2 NaClO3 --> 2 NaCl + 3 O2

2 mole NaClO3 - 3 moles O2

x - 2,28*10^-3 moles O2

X= 1,52*10^-3 moles of NaClO3

1 moles of NaClO3 - 106,44 g

1,52*10^-3 moles of NaClO3 - y

y = 0,1617 g

0,8765 g - 100%

0,1617 g - z

z = 18,46%

8 0
3 years ago
How many grams are in 2.50 moles of copper?
Tcecarenko [31]

Answer:

There are 63.546 grams in a 2.50 moles of copper.

3 0
3 years ago
Please helpppppppppp
IgorC [24]

Answer:

Plants take carbon dioxide from the air and use it to make food.

Explanation:

4 0
3 years ago
Read 2 more answers
Ethanol is added to gasoline because the oxygen it contains improves gasoline's burning efficiency. Its combustion reaction is g
ruslelena [56]

Answer:

A) The reaction is exothermic reaction

B) 46 gm CH3CH2OH  = 1236KJ

15.3 gm ch3ch2OH = 1236/46 x 15.3

= 411.10 KJ..........released

therefore  1 KJ = 0.239 K cal

so, 411.10 x 0.239 kcal

= 98.2529 .................. released

c) 54 gm of H2O produced = 1236KJ

so, 42.7 gm H2O produced = 1236/54 x 42.7KJ

= 977.35 KJ released.

Explanation:

7 0
3 years ago
What is the molarity of a solution prepared by dissolving 36. 0 g of naoh in enough water to make 1. 50 l of solution?
Vlada [557]

0.6 mol / L is the molarity of a solution prepared by dissolving 36. 0 g of NaOH in enough water to make 1. 50 l of solution.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another term for molarity.

The ratio employed to indicate the solution's concentration is called its molarity. Understanding a solution's molarity is important since it allows you to determine the actual concentration as well as whether the solution is diluted or concentrated.

Amount of NaOH = 36. 0 g

Amount of water = 1. 50 L

1 mol of NaOH = 40 g,

Moles of NaOH = 36. 0 / 40 g = 0.9 mol NaOH

Molarity of a solution = moles of solute / Liters of solution

Molarity of a solution = 0.9 / 1.50

Molarity of a solution = 0.6 mol / L

To  know more about Molarity refer to:  brainly.com/question/8732513

#SPJ4

4 0
1 year ago
Other questions:
  • 1.8 x 1022 atoms of Rn to moles of Rn​
    7·1 answer
  • How many moles are in 564 grams of Copper
    9·1 answer
  • How are molecules built?
    12·2 answers
  • Most chemical reactions involve the evolution or absorption of heat energy. True or False
    9·1 answer
  • Rank the following elements by effective nuclear charge, Zeff, for a valence electron.F LI Be B N
    5·2 answers
  • Please I need it asap
    9·2 answers
  • Rank the effective nuclear charge Z* experienced by a valence electron in each of these atoms:
    5·1 answer
  • Matter doesn't have to take up space as long as it has mass.
    11·2 answers
  • Which statement best explains why the elements in Group 18 do not have electronegativity values?
    7·1 answer
  • Write a balanced equation for the reaction<br>between ammonia and sulfuric acid?​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!