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sergeinik [125]
2 years ago
6

A Certain gas weighs 60g. IF the relative molecular mass of the gas is 12 what is the volume of the gas?​

Chemistry
1 answer:
GaryK [48]2 years ago
8 0
Hm I’m not sure could you support more detail
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Do bases react with metals the same way that acids do?.
mina [271]

Answer:

Bases do not react with metals in the way that acids do

Explanation:

hope this helps

pls mark brainliest

6 0
1 year ago
Based on the balanced chemical equation for the preparation of malachite, what is the composition of the bubbles formed when sod
spin [16.1K]

Answer:

Carbon Dioxide = CO2

Explanation:

The synthesis of Malachite is seen in the chemical formula:

CuSO 4 . 5H2O(aq) + 2NaCO3(aq) --> CuCO 3 Cu(OH) 2 (s) + 2Na 2 SO 4 (aq) + CO 2 (g) + 9H 2 O(l)

The bubbles mentioned in the question hints that our interest is the compounds in their gseous phase  (g).

Upon examining the chemical equation, only CO2 is in the gaseous state and hence the only one that can be formed as bubbles,

3 0
3 years ago
Calculate the mass of sodium azide required to decompose and produce 2.104 moles of nitrogen. Refer to the periodic table to get
Alexxx [7]

91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

Explanation:

2NaN3======2Na+3N2

This  is the balanced equation for the decomposition and production of sodium azide required to produce nitrogen.

From the equation:

2 moles of NaNO3 will undergo decomposition to produce 3 moles of nitrogen.

In the question moles of nitrogen produced is given as 2.104 moles

so,

From the stoichiometry,

3N2/2NaN3=2.104/x

= 3/2=2.104/x

3x= 2*2.104

   = 1.4 moles

So, 1.4 moles of sodium azide will be required to decompose to produce 2.104 moles of nitrogen.

From the formula

no of moles=mass/atomic mass

        mass=no of moles*atomic mass

                   1.4*65

               = 91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

4 0
3 years ago
How many joules are needed to warm 675 grams of water (specific heat= 4.186 J/g degrees Celsius) from 12 degrees Celsius to 85 d
Naya [18.7K]
85-12 = 73 degrees needed
4.186 J/degree Celsius, so 
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J

2.06 x 10^5 J are needed
3 0
3 years ago
Read 2 more answers
Using the periodic table, complete the following. Element: hydrogen symbol: H₂ Molecular weight: g Mass of one mole: g/mol
NNADVOKAT [17]

I think the mass is 88.54g/mol.

7 0
3 years ago
Read 2 more answers
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