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patriot [66]
2 years ago
13

HELP ASAP!!!!!! I NEED HELP

Chemistry
1 answer:
Whitepunk [10]2 years ago
6 0

The organs of the digestive system such as the pancreas, liver, stomach, small intestine, and large intestine help in the digestion of food.

<h3>What are organs?</h3>

Organs are a collection of tissues that are closely related and which perform a related function.

The role and function of the organs of the digestive system are as follows:

  • Pancreas - produces pancreatic juice which contain digestive enzymes
  • Liver - produces bile for the emulsification of fat
  • Stomach - serves as a temporary store of food and produces digestive juices
  • Small intestine - functions in food digestion
  • Large Intestine - helps to remove undigested food from the body

Therefore, the organs of the digestive system such as the pancreas, liver, stomach, small intestine, and large intestine help in the digestion of food.

Learn more about digestive system at: brainly.com/question/956634

#SPJ1

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A linear graph with a slope of zero would indicate which of the following?
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As the independent variable changes, the dependent variable never changes.

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Determine the number of moles of N atoms in 46.5g of Mg(NO3)2
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First, we determine the moles of Mg(NO₃)₂ present:
moles = mass / Mr
= 46.5 / (24 + 2 x (14 + 16 x 3))
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Each mole of Mg(NO₃)₂ contains 2 moles of Nitrogen atoms.
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BRAINLIEST!!! <br> Is it A or D? <br> Can someone help me?
son4ous [18]

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A

Explanation:

Hope this helps!

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Even about the food chain is correct?​
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Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con
anyanavicka [17]

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0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.

Explanation:

¡Hola!

En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:

Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3

Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:

2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 }  *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O}  *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3

De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.

¡Saludos!

5 0
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