Question

350.0-mL of 0.50 M hydrogen sulfate solution is reacted with 15.0 grams of sodium hydroxide. What volume of water will be produced?​

Answer 1

The volume of water that will be produced from the reaction will be 6.3 mL

Stoichiometric calculation

From the equation of the reaction:

$H_2SO_4 + 2NaOH --- > Na_2SO_4 + 2H_2O$

The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.

Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles

Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles

Thus, hydrogen sulfide is the limiting reagent.

Mole ratio of hydrogen sulfide to water = 1:2.

Equivalent mole of water = 0.175 x 2 = 0.35 moles

Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.

1 gram of water = 1 ml.

Thus, 6.3 grams of water will be equivalent to 6.3 mL

More on stoichiometric calculation can be found here: brainly.com/question/27287858

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