350.0-mL of 0.50 M hydrogen sulfate solution is reacted with 15.0 grams of sodium hydroxide. What volume of water will be produc
1 answer:
The volume of water that will be produced from the reaction will be 6.3 mL
<h3>Stoichiometric calculation</h3>From the equation of the reaction:
The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.
Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles
Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles
Thus, hydrogen sulfide is the limiting reagent.
Mole ratio of hydrogen sulfide to water = 1:2.
Equivalent mole of water = 0.175 x 2 = 0.35 moles
Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.
1 gram of water = 1 ml.
Thus, 6.3 grams of water will be equivalent to 6.3 mL
More on stoichiometric calculation can be found here: brainly.com/question/27287858
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<u>Answer:</u> The isotopic symbol of barium is and that of strontium is
<u>Explanation:</u>
Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.
In a nuclear reaction, the total mass and total atomic number remains the same.
- For the given fission reaction:
- <u>To calculate A:</u>
Total mass on reactant side = total mass on product side
235 + 1 = A + 94 + 3
A = 139
- <u>To calculate Z:</u>
Total atomic number on reactant side = total atomic number on product side
92 + 0 = Z + 36 + 0
Z = 56
The isotopic symbol of barium is
- For the given fission reaction:
- <u>To calculate A:</u>
Total mass on reactant side = total mass on product side
235 + 1 = A + 143 + 3
A = 90
- <u>To calculate Z:</u>
Total atomic number on reactant side = total atomic number on product side
92 + 0 = Z + 54 + 0
Z = 38
The isotopic symbol of strontium is
Hence, the isotopic symbol of barium is and that of strontium is