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Alex17521 [72]
3 years ago
9

Which property of the wave makes it-(C)

Physics
2 answers:
AlekseyPX3 years ago
4 0

Answer:

low amplitude hope it will help you

mylen [45]3 years ago
4 0
The first one
explanation: i took the test so i know what the answer is :)
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Cho các máy cắt sử dụng trong công nghiệp có ký hiệu trên nhãn thiết bị: C350; B500. Hãy tính dòng điện bảo vệ ngắn mạch và dòng
solniwko [45]

Answer:

ask in the English then I can help you

Explanation:

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3 0
3 years ago
Which kind of radio waves are used by television stations to carry sound?
pochemuha
They are called <span>Frequency-modulated</span>
5 0
4 years ago
If you push a crate horizontally with 100 N across a 10 m factory floor and the friction between the crate and the floor is a st
erik [133]

Answer:

300 J

Explanation:

First of all, we need to calculate the net force acting on the crate, which is given by:

F_{net} = F-F_f

where

F = 100 N is the horizontal push

F_f = 70 N is the force of friction

Substituting,

F_{net}=100 - 70 = 30 N

Now we can calculate the net work done on the crate:

W=F_{net}d

where

d = 10 m is the displacement

Substituting,

W=(30)(10)=300 J

According to the work-energy theorem, the kinetic energy gained by the crate is equal to the work done on it: therefore, the answer is 300 J.

4 0
3 years ago
Two small plastic spheres are given positive electrical charges. When they are a distance of 14.8cm apart, the repulsive force b
sdas [7]

Answer:

Explanation:

Case I: They have same charge.

Charge on each sphere = q

Distance between them, d = 14.8 cm = 0.148 m

Repulsive force, F = 0.235 N

Use Coulomb's law in electrostatics

F=\frac{Kq_{1}q_{2}}{d^{2}}

By substituting the values

0.235=\frac{9\times10^{9}q^{2}}{0.148^{2}}

q=7.56\times10^{-7}C

Thus, the charge on each sphere is q=7.56\times10^{-7}C.

Case II:

Charge on first sphere = 4q

Charge on second sphere = q

distance between them, d = 0.148 m

Force between them, F = 0.235 N

Use Coulomb's law in electrostatics

F=\frac{Kq_{1}q_{2}}{d^{2}}

By substituting the values

0.235=\frac{9\times 10^{9}\times 4q^{2}}{0.148^{2}}

q=3.78\times10^{-7}C

Thus, the charge on second sphere is q=3.78\times10^{-7}C and the charge on first sphere is 4q = 4\times 3.78\times 10^{-7}=1.51 \times 10^{-6} C.

6 0
3 years ago
Help with speed problems #1-3
-Dominant- [34]
1. Each plot represents the meters traveled by both the Hare and the Tortoise over a certain period of time (minutes).

2. The Tortoise lines show it lines is steadily increasing over a period of time. So as more time elapses the faster the tortoise becomes it travels more meters. The Tortoise line shows steady acceleration.

3. The Hare in the first 5 minutes had a rapid fast advancement up to 40 meters. But for the 5-20 mins. period the Hare did not move at all. Its speed stayed at the same place. But towards the end 20-25 mins. marks the Hare started moving again. At the end the Hare at first had a rapid acceleration but stopped for a long time then it sped up briefly. 
8 0
3 years ago
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