Ask question

Ask question

All categories

3 years ago

9

Which property of the wave makes it-(C)

2 answers:

AlekseyPX3 years ago

4 0

Answer:

low amplitude hope it will help you

mylen [45]3 years ago

4 0

The first one
explanation: i took the test so i know what the answer is :)

You might be interested in

What is not changed when work is done by a machine?

Irina18 [472]

B) The amount of work done

8 0

3 years ago

Read 2 more answers

The curved movement of air or water is the result of which of these?

ella [17]

<h3><u>Answer;</u></h3>

B. the rotation of Earth on its axis

<h3><u>Explanation;</u></h3>

<em><u>The Coriolis effect describes how the Earth's rotation steers winds and surface ocean currents. The Coriolis effect causes the motion of a freely moving object to appear as a curve.</u></em>
<em><u>Therefore, since air and water move freely, the Coriolis effect makes their movement to be curved. This is why the movement of winds and oceans does not follow a straight line but it is bent and curved.</u></em>

8 0

4 years ago

Read 2 more answers

A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long

Degger [83]

Answer:

(A). The work done by friction in crossing the patch is -637.98 J.

(B). The speed of skier is 10.57 m/s.

Explanation:

Given that,

Mass of skier = 62 kg

Speed = 6.5 m/s

Length = 3.50 m

Coefficient kinetic friction = 0.30

Height = 2.5 m

(A) we need to calculate the work done by friction in crossing the patch

Using formula of work done

$W=-\mu mg\times l$

Put the value into the formula

$W=-0.30\times62\times9.8\times3.50$

$W=-637.98\ J$

The work done by friction in crossing the patch is -637.98 J.

(B) we need to calculate the speed of skier

Using conservation of energy

$K.E_{i}+U_{i}-W_{friction}=K.E_{f}+U_{f}$

$\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2+U_{f}$

Final potential energy is zero

So, $\dfrac{1}{2}mv_{1}^2+mgh-\mu mgl=\dfrac{1}{2}mv_{2}^2$

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}v_{1}^2+gh-\mu gl$

Put the value into the formula

$\dfrac{1}{2}v_{2}^2=\dfrac{1}{2}\times6.5^2+9.8\times2.5+0.30\times9.8\times3.50$

$v_{2}=\sqrt{2\times55.915}$

$v_{2}=10.57\ m/s$

The speed of skier is 10.57 m/s.

Hence, (A).The work done by friction in crossing the patch is -637.98 J.

(B).The speed of skier is 10.57 m/s.

6 0

3 years ago

What are the units used to measure specific heat capacity?.

Nuetrik [128]

The units used to measure specific heat capacity is Joules per kilogram per Kelvin.

<h3>What is specific heat capacity?</h3>

It is the amount of heat absorbed per kilogram of material when the temperature rises by 1 kelvin.

Specific heat capacity C is the Joules of energy in form of heat per kilogram per Kelvin temperature. The units represented by

C = ___ J/kg.K

Thus, the units used to measure specific heat capacity is Joules per kilogram per Kelvin.

Learn more about specific heat capacity.

brainly.com/question/1747943

#SPJ4

6 0

3 years ago

a person throws a ball in such a way that its speed is zero at one particular point in its path. How did the person throw the ba

Keith_Richards [23]

vertical! or in other words, up!

6 0

4 years ago