Acceleration (magnitude anyway) = (change in speed) / (time for the change) .
Change in speed = (10 - 30) = -20 m/s
Time for the change = 4.0sec
Magnitude of acceleration = -20/4 = <em>-5 m/s² </em>
Newton's second law allows calculating the response for the person's acceleration while leaving the trampoline is:
-4.8 m / s²
Newton's second law says that the net force is proportional to the product of the mass and the acceleration of the body
F = m a
Where the bold letters indicate vectors, F is the force, m the masses and the acceleration
The free body diagram is a diagram of the forces without the details of the body, in the attached we can see the free body diagram for this system
-W = m a
Whera
is the trampoline force
Body weight is
W = mg
We substitute
- mg = ma
a =
Let's calculate
a = 
a = -4.8 m / s²
The negative sign indicates that the acceleration is directed downward.
In conclusion using Newton's second law we can calculate the acceleration of the person while leaving the trampoline is
-4.8 m / s²
Learn more here: brainly.com/question/19860811
Answer:
The answer is a wedge.
Explanation:
The wedge is a combination of two inclined planes. It is used to separate bodies which are held together by large forces, e.g, splitting timber
M.A.= slant height of wedge/thickness of wedge.
Hence a long thin wedge has a higher mechanical advantage than a short thick one; or the smaller the angle theta between the slant heights, the greater the mechanical advantage.
Explanation:
Force = Mass × Acceleration
Mass = 150kg
Acceleration = 5 m/s^2
Force = 150 × 5 = 750N
Answer:
The period would be 0.0034 seconds
Explanation:
The d string has a frequency of 293 Hz when it is in tune
So the period of D string is 0.0034 seconds