3.01× 1024 particles are the number of particles are there in 5 grams of sodium carbonate.
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How many particles are there in 5 grams of sodium carbonate?</h3>
There are 6.022 × 1023 particles in one gram of a substance according to Avogadro's number. So when we find out for 5 grams, then we multiply 5 with 6.022 × 1023, we get 3.01 × 1024 particles. For one gram atomic weight of hydrogen, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms.
So we can conclude that 3.01× 1024 particles are the number of particles are there in 5 grams of sodium carbonate.
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The volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
HOW TO CALCULATE VOLUME OF ETHANOL:
- According to this question, a particular beer is 65.0% ethanol by volume. This means that the beer contains 65/100 of ethanol.
- If a single bottle of beer contains a total of 750.0 mL of beer, the volume of ethanol in the bottle is calculated as follows:
- Therefore, volume in mL of ethanol (C₂H₆O) present in the bottle is 487.5L
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Answer: The Sun Could Be Seen Once during the year when north of the equator.
If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.
<h3>What is Stoichiometry ?</h3>
Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
Mg + 2HNO₃ → Mg(NO₃)₂ + H₂
According to Stoichiometry
= 3.3 g H₂
Thus from the above conclusion we can say that If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.
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